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Dovator [93]
3 years ago
5

NEED HELP FAST PLEASE Evaluate the limit. a.4 c.1 b.2 d.limit does not exist

Mathematics
1 answer:
BlackZzzverrR [31]3 years ago
7 0
We have the following limit:
 (8n2 + 5n + 2) / (3 + 2n)
 Evaluating for n = inf we have:
 (8 (inf) 2 + 5 (inf) + 2) / (3 + 2 (inf))
 (inf) / (inf)
 We observe that we have an indetermination, which we must resolve.
 Applying L'hopital we have:
 (8n2 + 5n + 2) '/ (3 + 2n)'
 (16n + 5) / (2)
 Evaluating again for n = inf:
 (16 (inf) + 5) / (2) = inf
 Therefore, the limit tends to infinity.
 Answer:
 
d.limit does not exist
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Answer:

P = 0.05

Step-by-step explanation:

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10(-2*-2*-2)(-3*-3)

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7 0
3 years ago
Please use system of linear equations by elimination OR substitution. I need the work as well please.
Olin [163]

1) P= 64 cm, width = x, length = 14 + x

64 = x + x + 14 + x + 14 + x

64 = 4x + 28

4x = 64 - 28

4x = 36

x = 36/ 4

x = 9

AREA = 9 x (9+14)

Area = 9 x 23

Area = 207 cm

2) smaller no. = y, bigger no. = x

x - y = 3

2x+1/2y=36

Next, multiply 2 to first equation and find y:

2x-2y=6

5/2y=30

y = 12

Substitue y to x-y=3 to find x,

x = 15

3) x = pencil, y = pen

5x + 4y = $6.15

8x + 3y = 9.85$

8x + 7y = ?

5x + 4y = 6.15$ multiply both sides by -3

8x + 3y = 9.85$ multiply both sides by 4

-15x + 32x = (-3)*6.15 + 4*9.85

7x = 19.87 multiply both sides by 8/7

8x = (8/7) x 19.87

Add both equations:

32y - 15y = 8x6.15 - 5*9.58

17y = 1.3

y = 91/17) x 1.3

7y = (7/17)x 1.3

8x + 7y = (8/7) x 19.87 + (7/17) x 1.3

8x + 7y = $23.244

4) 2l + 2w = 0

2 x 2l + 2 x 1/2w = 40 + 16

l+w = 20

4l+w = 56

I’ve got l = 12 and w = 8

5) answer:   28.56 feet (approx)

step-by-step explanation:

since, triangle abc has measure of angle c equal to 55 degrees, measure of angle abc equal to 90 degrees, and length of bc equal to 20 feet.

we have to find out the measurement of segment ab.

therefore, tan 55° = \frac{ab}{bc}

but bc = 20 feet.

⇒ tan 55 ° =   \frac{ab}{20}

⇒ ab = 20 × tan 55 °

⇒ ab = 20 × 1.42814800674

⇒ ab = 28.5629601348   ≈ 28.56 feet

6) The answer is teh attachment !

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The domain is the set of all real numbers (both positives and negatives including zero.

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