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Dovator [93]
3 years ago
5

NEED HELP FAST PLEASE Evaluate the limit. a.4 c.1 b.2 d.limit does not exist

Mathematics
1 answer:
BlackZzzverrR [31]3 years ago
7 0
We have the following limit:
 (8n2 + 5n + 2) / (3 + 2n)
 Evaluating for n = inf we have:
 (8 (inf) 2 + 5 (inf) + 2) / (3 + 2 (inf))
 (inf) / (inf)
 We observe that we have an indetermination, which we must resolve.
 Applying L'hopital we have:
 (8n2 + 5n + 2) '/ (3 + 2n)'
 (16n + 5) / (2)
 Evaluating again for n = inf:
 (16 (inf) + 5) / (2) = inf
 Therefore, the limit tends to infinity.
 Answer:
 
d.limit does not exist
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F(x)=1/2x+2.i need help
m_a_m_a [10]

Answer: If you want to find the x and y intercepts, your answer would be...

x-intercept - (-4,0)

y-intercept - (0,2)

Step-by-step explanation:

To find the x-intercept, substitute in 0 for y and solve for x. To find the y-intercept, substitute in 0 for x and solve for y.

I hope this helps you out! ☺

8 0
3 years ago
The escalator rises 25° from the ground and a vertical distance of 42 feet. How much horizontal distance does the escalator cove
zvonat [6]
Tangent (25) = opp / adj = 42 / horizontal distance
horizontal distance =  42 / tangent (25)
horizontal distance = 42 / 0.46631
horizontal distance = <span> <span> <span> 90.068838326435200 </span> </span> </span>
horizontal distance = 90.1 feet


5 0
2 years ago
If 5^2x+1 = 96, Then find x
Mkey [24]
Jkeoeodiekqnsnabbdbw
6 0
3 years ago
What are the coordinates of its image, J'KL, if this
shtirl [24]

Answer:

J'(-15,10)\\\\K'(15,10)\\\\L'(0,-20)

Step-by-step explanation:

For this exercise you must remember that the original figure (before a transformation) is called "Pre-Image" and the one obtained after the transformation is called "Image".

 Dilation is defined as a transformation in which the Image and the Pre-Image have the same shape, but different sizes.

If a figure is dilated by a scale factor "k" with respect to the origin, the rule is:

(x,y) → (kx,ky)

In this case, the vertices of the triangle JKL (the Pre-Image) are:

J(-3.2)\\\\K(3,2)\\\\L(0,-4)

Knowing that the scale factor is:

k=5

You get that the vertices of the triangle J'K'L' (Image), are:

J'=(5(-3),5(2))=(-15,10)\\\\K'=(5(3),5(2))=(15,10)\\\\L'=(5(0),5(-4))=(0,-20)

7 0
2 years ago
Read 2 more answers
1 over 4a = 2 over 3. Which of the following equals a in this equation?
ch4aika [34]
   1             2
------- =  --------
  4a           3

cross multiply
2(4a) = 1 * 3
8a = 3
  a = 3/8 or a = 3 over 8

answer
<span>3 over 8</span>
6 0
3 years ago
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