Answer : The volume for 6.0m HCl solution required = 62.5 ml
Solution : Given,
Initial concentration of HCl solution = 6.0m
Final concentration of HCl solution = 1.5m
Final volume of HCl solution = 250 ml
Initial volume of HCl solution = ?
Formula used for dilution is,

where,
= initial concentration
= final concentration
= initial volume
= final volume
Now put all the given values in above formula, we get the initial volume of HCl solution.

= 62.5 ml
Therefore, the volume for 6.0m HCl solution required = 62.5 ml
The complete reaction along with intermediates is given below, with each step highlighted in different color.
Step 1: In this step an acidic proton at alpha position is abstracted from lactone moiety and corresponding enolate is formed, which is resonance stabilized. Both structures are shown. In this case LDA (<span>Lithium diisopropylamide) acts as a base.
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Step 2: The enolate formed attacks on Methyl Iodide, as Iodide being greater in size is a good leaving group and alpha methyl moiety is generated.
Step 3: This step is acid catalyzed Bromination. Bromine is added at alpha position.
Step 4: This is elimination reaction and is according to <span>Hofmann's Rule. Here less substituted alkene is generated.</span>
Answer:
non-metal
Explanation:
The element has 5 electrons on last energy level, so given element is non-metal. Most Metals have 1 or 2 electrons on the last level.