Answer:
½O 2 + 2e - + H 2O → 2OH.
Explanation:
Redox reactions - Higher
In terms of electrons:
oxidation is loss of electrons
reduction is gain of electrons
Rusting is a complex process. The example below show why both water and oxygen are needed for rusting to occur. They are interesting examples of oxidation, reduction and the use of half equations:
iron loses electrons and is oxidised to iron(II) ions: Fe → Fe2+ + 2e-
oxygen gains electrons in the presence of water and is reduced: ½O2 + 2e- + H2O → 2OH-
iron(II) ions lose electrons and are oxidised to iron(III) ions by oxygen: 2Fe2+ + ½O2 → 2Fe3+ + O2-
The reaction is:
<span>4Li(s) + O2 (g) = 2Li+ + 2O-2(s).
The oxidizing agent is the one that is being reduced which is oxygen where the charge changed from neutral to -2 while the reducing agent is the on being oxidized which is lithium where the charge change from neutral to +1.</span>
Four different substituents are required on a carbon atom for it to be chiral.
<h3>What is Chiral Carbons ?</h3>
The carbon atom which is attached with four different types of group of atoms or atoms is called Chiral carbon. Chiral molecules are non superimposable on their mirror images. Chiral carbon is also called asymmetric carbon.
Example:

In the above example we can see that carbon atom has 4 different group attached with it that is Br, Cl, H, CH₃.
Thus from the above conclusion we can say that Four different substituents are required on a carbon atom for it to be chiral.
Learn more about the Chiral carbon here: brainly.com/question/1195366
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