Question

How many mL of a 6 M NaOH stock solution is needed in order to prepare 500 mL of a 0.2 M NaOH solution?

Answer 1

Answer:

The right answer is "16.67 mL".

Explanation:

Given:

Molarity of NaOH,

$M_1=6 \ M$

$M_2=0.2 \ M$

Volume of NaOH,

$V_1=V \ mL$

$V_2=500 \ mL$

As we know, the equation,

⇒ $M_1V_1=M_2V_2$

On putting the values, we get

⇒ $6\times V=0.2\times 500$

⇒ $6\times V=100$

⇒        $V=\frac{100}{6}$

⇒            $=16.67 \ mL$