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sergejj [24]
4 years ago
6

What is the product when x-5 is multiplied by2x+3

Mathematics
1 answer:
mote1985 [20]4 years ago
3 0

Answer:

13

Step-by-step explanation:

1. Put 5 in for x. 2×5+3

2.10+3

3.13

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BARSIC [14]
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She said that I don’t need her 54
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3 years ago
Which step is wrong, Step 1, Step 2, Step 3 or Li didn't make a mistake
mart [117]
Hello there!


The correct answer is option A

Instead of the division sign, it suppose to be multiply.

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7 0
3 years ago
It is a six-digit
KonstantinChe [14]
Ok, the first clue is it has six digit and the second clue is it’s a whole number!
So we know it lies between 99999 and 1000000
3rd clue tells it has only 3 different digits and 4th clue tells us each are used twice!
Moving on, 5th clue says none of its digits are even! 6th speaks none are divisible be 3
So the possibilities for digits are 1, 5, 7
And it’s greater than 600000, then the 1st digit must be 7! It is divisible be 5, so last digit must be 5!
7th clue states that It’s tenth digit is same as hundred-thousand! Means the tenth digit is 7
Let’s see what we got!
{7xxx75}
Clue no 8 as you can see says that it’s thousands digit is same as unit digit
So the number now is {7x5x75}
9th clue says it’s hundreds digit is different from tens digit meaning the hundreds digit is either 1 or 7 and we used 7 two times, so it’s 1 and clue 10 says it’s ten thousands digit is 1 so the number that’s playing hide ‘n seek or most probably riddle game is 715175!
8 0
3 years ago
Three cards are drawn from a standard deck of 52 cards without replacement. Find the probability that the first card is an ace,
MrRissso [65]

Answer:

4.82\cdot 10^{-4}

Step-by-step explanation:

In a deck of cart, we have:

a = 4 (aces)

t = 4 (three)

j = 4 (jacks)

And the total number of cards in the deck is

n = 52

So, the probability of drawing an ace as first cart is:

p(a)=\frac{a}{n}=\frac{4}{52}=\frac{1}{13}=0.0769

At the second drawing, the ace is not replaced within the deck. So the number of cards left in the deck is

n-1=51

Therefore, the probability of drawing a three at the 2nd draw is

p(t)=\frac{t}{n-1}=\frac{4}{51}=0.0784

Then, at the third draw, the previous 2 cards are not replaced, so there are now

n-2=50

cards in the deck. So, the probability of drawing a jack is

p(j)=\frac{j}{n-2}=\frac{4}{50}=0.08

Therefore, the total probability of drawing an ace, a three and then a jack is:

p(atj)=p(a)\cdot p(j) \cdot p(t)=0.0769\cdot 0.0784 \cdot 0.08 =4.82\cdot 10^{-4}

4 0
4 years ago
Spiral Review At a restaurant, Brianna and Naomi each order an appetizer for $6.50 and an entree for $9.75. They decide to leave
Licemer1 [7]

Answer: 4.55

Step-by-step explanation:

6.50x2 = 13 + 9.75 = 20% = 4.55

hoped this helped lol

4 0
3 years ago
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