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3 years ago

11

Writing an equation of a proportional relationship in the form y=kx k represents the

1 answer:

Luden [163]3 years ago

8 0

A proportional relationship is a relationship between two quantities in which the ratio of one quantity to the other quantity is constant. A proportional relationship can be described by an equation of the form y = kx, where k is a number called the constant of proportionality.

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On an algebra test, there are 7 students with As, 9 students with Bs, 11 students with Cs, 3 students with Ds, and 2 students wi

klemol [59]

Students with D's / total students : 3 / (7 + 9 + 11 + 3 + 2) =
3 / 32 = 0.0937...to turn to a percent, multiply by 100 = 9.375....rounded =
9.4% <== ur probability

3 0

2 years ago

Solve the initial value problem: y'(x)=(4y(x)+25)^(1/2) ,y(1)=6. you can't really tell, but the '1/2' is the exponent

goblinko [34]

Answer:

$y(x)=x^2+5x$

Step-by-step explanation:

Given: $y'=\sqrt{4y+25}$

Initial value: y(1)=6

Let $y'=\dfrac{dy}{dx}$

$\dfrac{dy}{dx}=\sqrt{4y+25}$

Variable separable

$\dfrac{dy}{\sqrt{4y+25}}=dx$

Integrate both sides

$\int \dfrac{dy}{\sqrt{4y+25}}=\int dx$

$\sqrt{4y+25}=2x+C$

Initial condition, y(1)=6

$\sqrt{4\cdot 6+25}=2\cdot 1+C$

$C=5$

Put C into equation

Solution:

$\sqrt{4y+25}=2x+5$

or

$4y+25=(2x+5)^2$

$y(x)=\dfrac{1}{4}(2x+5)^2-\dfrac{25}{4}$

$y(x)=x^2+5x$

Hence, The solution is $y(x)=\dfrac{1}{4}(2x+5)^2-\dfrac{25}{4}$ or $y(x)=x^2+5x$

4 0

2 years ago

Write 0.000739 in scientific notation.

jek_recluse [69]

Answer:

7.39 × 10-4^-4

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

PLs HeLP !!!<br><br> multiply <br> (-8) x 11

DochEvi [55]

Answer:

-88

Step-by-step explanation:

11*8=88 put the negative sign with it and you get -88

8 0

3 years ago

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WILL MARK BRAINLIEST! If you buy 3 pounds of hamburg for $8.97, how much will it cost for 5 pounds of hamburg?

liubo4ka [24]

Answer:

14.95

Step-by-step explanation:

every 1 pound is 2.99 so you would do 2.99 * 5

6 0

3 years ago

Read 2 more answers