Answer:
5.158 × 10²³ atoms K
General Formulas and Concepts:
<u>Chemistry - Atomic Structure</u>
- Reading a Periodic Table
- Using Dimensional Analysis
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
Explanation:
<u>Step 1: Define</u>
33.49 g K
<u>Step 2: Identify Conversions</u>
Avogadro's Number
Molar Mass of K - 39.10 g/mol
<u>Step 3: Convert</u>
<u />
= 5.15797 × 10²³ atoms K
<u>Step 4: Check</u>
<em>We are given 4 sig figs. Follow sig figs and round.</em>
5.15797 × 10²³ atoms K ≈ 5.158 × 10²³ atoms K
D = m / V
3.26 = m / 0.313
m = 3.26 x 0.313
m = 1.02038 g
hope this helps!
The ion is Al³⁺
mass number - number of neutrons= atomic number
27 - 14 = 13
Aluminum has an atomic number of 13, thus we know this is the metal in question. Also, because the aluminum has only 10 electrons, (3 less than a neutral atom of aluminum would have), its charge must be 3+