Hello,
<span>the gas phase is [Ar] 3d^5 4s^2 and since there are five 3d AOs the atom has five unpaired e⁻: (↑)(↑)(↑)(↑)(↑) (Hund's rule)</span>
Answer: The rate of the loss of is 0.52M/s
Explanation:
Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.
The rate in terms of reactants is given as negative as the concentration of reactants is decreasing with time whereas the rate in terms of products is given as positive as the concentration of products is increasing with time.
Rate of disappearance of =
Rate of formation of =
Rate of formation of =
Thus Rate of disappearance of =
112 L/ 16 L = 7 mol O2
7 mol O2 x 2 mol Fe2O3/ 3 mol O2 = 4.67 mol Fe2O3
lmk if its right
Answer:
4
Explanation:
A carbon atom has 4 electrons in its outermost shell (2s^2p^2). All are unpaired (none share their orbital with another electron). So all four are anxious to pair with another electron. Once it has found 4 more electrons contributed from other atom(s), it will have 4 pairs of shared electrons.
Hydrogen has one lone electron. An atom of H is downright gleeful in sharing it's electron with elements such as carbon, C. Since carbon has 4 unpaied electrons, it will combine with 4 H atoms. At that point, cabon is sharing 4 electron pairs.