Answer is: because pure liquids (<span>shown in </span>chemical reactions<span> by appending (</span>l)<span> to the </span>chemical formula) and solids (<span>shown in </span>chemical equations by appending (s)<span> to the </span>chemical formula) not go in to he equilibrium constant expression, only gas state (shown in chemical reactions by appending (g) to the chemical formula) reactants and products go in to he equilibrium constant expression.
For example, equilibrium constant expression Kp for reaction:
A(s) + 2B(s) ⇄ 4C(g) + D(g).<span>
will be: Kp = [C]</span>⁴<span>·[D].
But for reaction </span>A(g) + 2B(g) ⇄ 4C(g) + D(g), will be:<span>
Kp = [C]</span>⁴<span>·[D] / [A]·[B]².</span>
Explanation:
b and c are true statements
Answer:
450g of coke (C)
Explanation:
Step 1:
The balanced equation for the reaction is given below:
3C(s) + 2SO2(g) —> CS2(s) + 2CO2(g)
Step 2:
Determination of the mass of C that reacted and the mass of CS2 produced from the balanced equation.
This is illustrated below:
Molar Mass of C = 12g/mol
Mass of C from the balanced equation = 3 x 12 = 36g
Molar Mass of CS2 = 12 + (32x2) = 12 + 64 = 76g/mol.
From the balanced equation above, 36g of C reacted to produce 76g of CS2.
Step 3:
Determination of the mass of C required to produce 950g of CS2. This is illustrated below:
From the balanced equation above, 36g of C reacted to produce 76g of CS2.
Therefore, Xg of C will react to produce 950g of CS2 i.e
Xg of C = (36 x 950)/76
Xg of C = 450g
From the calculations made above, 450g of coke (C) is needed to produce 950g of CS2.
Answer:materials that impede the free flow of electrons from atom to atom and molecule to molecule.
