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3 years ago

solve for the indicated variable. include all of your work in your answer. submit your solution. A=1+prt; for r

1 answer:

4 0

Step 1. Subtract 1 from bot sides of the equation:
$A-1=1-1+prt$
$A-1=prt$

Step 2. Divide both sides of the equation by $pt$ :
$\frac{A-1}{pt} = \frac{prt}{pt}$
$\frac{A-1}{pt}=r$
$r=\frac{A-1}{pt}$

We can conclude that after solving the equation A=1+prt; for r, we get $r=\frac{A-1}{pt}$

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Use Lagrange multipliers to find the maximum and minimum values of f(x,y)=x+4y subject to the constraint x2+y2=9, if such values

Vesnalui [34]

The Lagrangian is

$L(x,y,\lambda)=x+4y+\lambda(x^2+y^2-9)$

with critical points where the partial derivatives vanish.

$L_x=1+2\lambda x=0\implies x=-\dfrac1{2\lambda}$

$L_y=4+2\lambda y=0\implies y=-\dfrac2\lambda$

$L_\lambda=x^2+y^2-9=0$

Substitute $x,y$ into the last equation and solve for $\lambda$ :

$\left(-\dfrac1{2\lambda}\right)^2+\left(-\dfrac2\lambda\right)^2=9\implies\lambda=\pm\dfrac{\sqrt{17}}6$

Then we get two critical points,

$(x,y)=\left(-\dfrac3{\sqrt{17}},-\dfrac{12}{\sqrt{17}}\right)\text{ and }(x,y)=\left(\dfrac3{\sqrt{17}},\dfrac{12}{\sqrt{17}}\right)$

We get an absolute maximum of $3\sqrt{17}\approx12.369$ at the second point, and an absolute minimum of $-3\sqrt{17}\approx-12.369$ at the first point.

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2 years ago

Maci is paid biweekly and earns $1500 each paycheck. What is his yearly salary?

Pachacha [2.7K]

Your answer would be 36,000 because he gets 3000 every month and every month for a year he would get your answer which would be 3000×12 which equals 36,000

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3 years ago

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Leno4ka [110]

Answer:

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Step-by-step explanation:

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2 years ago

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Step-by-step explanation:

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2 years ago

Read 2 more answers

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kolezko [41]

Step-by-step explanation:

Add 75 to 12.55. the answer would be 87.55.

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2 years ago