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ser-zykov [4K]
2 years ago
15

if 2 man and 3 boys can do a piece of work in 8 days then how long do 3 man and 4 boys take to do the same work

Mathematics
2 answers:
frez [133]2 years ago
7 0

Answer:

hope this helps

Step-by-step explanation:

We will solve it by this way-

2 m and 3 b can do a work in 8 days.

Then 3 m and 4 b do it in how many days.

=2*3*8=3*4*x

x=2*3*8/3*4

x=2*8/4

x=2*2

x=4 days

sasho [114]2 years ago
7 0

Answer:

Send Them to me I'll figure it out Once They finish the job

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Please please please please please please please please answer as soon as possible. All answers are truly appreciated. Thank you
aliya0001 [1]
The answer 1 by 8x.25 = 2 and 4x.5squared making that 1
3 0
3 years ago
A rancher wishes to build a fence to enclose a rectangular pen having area 24 square yards. Along one side the fence is to be ma
Gnoma [55]

Answer:

The  value  is  C \approx \$76

Step-by-step explanation:

From the question we are told that

   The  area of the rectangular pen is  A =  24 \ yard^2

     The  cost of material used to make one side is  z = \$ 6

    The  cost of material used to make the other sides is  r  =  \$ 3

Now  , the fence to be build around the rectangular pen  has four sides, the first opposite sides are equal, let assume each of the to be x yard   and the other opposite sides are also equal as well let assume of the to be y yard

So the cost is mathematically represented as

       C =  zx  +  r (x + 2y )

=>   C =  6x  +  3(x + 2y)

=>   C =   9x  +  6y

Now the area of the fence is mathematically represented as

      A =  x* y =  24

=>    y  =  \frac{24}{x}

=>  C =   9x  +  6[\frac{24}{x} ]

=>   C =   9x  +  [\frac{144}{x} ]

Now differentiating

     C'  =  9 + 144*  (-2) x^{-2}

     C'  =  9 - 288x^{-2}

At minimum C' =  0

So  

     9 - 288x^{-2} =  0

     x^{-2} =  0.03125

    x =  \sqrt{\frac{1}{0.03125} }

    x =  5.66

Now substituting for x in the equation above to obtain minimum cost

       C =   9(5.66)  +  [\frac{144}{5.66} ]

       C \approx \$76

   

 

8 0
3 years ago
Kevin had a total of $320 to spend while shopping. He had spent $156 on video games. He wants to buy caps that are on sale for $
zloy xaker [14]

Maximum number of caps that Kevin can buy is 10.

Solution:

Total money for shopping = $320

Amount spent for video game = $156

Remaining amount that Kevin had = $320 – $156

                                                         = $164

Cost of each cap including tax = $15

$\text{Number of caps can buy }=\frac{\text { Remaining amount that Kevin had }}{\text { cost of each cap }}$

                                       $=\frac{164}{15}

                                      $=10\frac{14}{15}

Maximum number of caps that Kevin can buy is 10.

8 0
3 years ago
How do I answer this question?
bazaltina [42]
Yes because you use the distributive property
3 0
3 years ago
A = bh/2
Sliva [168]
To find A' they used the rule of multiplication, which is:

the derivative of a product of two terms is the first term times the derivative of the second term plus the second term times the derivative of the first.

To find b' they just isolated b'


6 0
3 years ago
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