Answer:
Mass= 2.77g
Explanation:
Applying
P=2.09atm, V= 1.13L, R= 0.082, T= 291K, Mm of N2= 28
PV=nRT
NB
Moles(n) = m/M
PV=m/M×RT
m= PVM/RT
Substitute and Simplify
m= (2.09×1.13×28)/(0.082×291)
m= 2.77g
Answer:
The final pressure of gas is 82.64 KNm⁻²
Explanation:
Given data:
Initial volume of gas = 180 cm³
Temperature of gas = 27°C
Initial pressure = 101 KNm⁻²
Final volume = 220 cm³
Final pressure = ?
Solution:
The given problem will be solved through the Boly's law,
"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"
Mathematical expression:
P₁V₁ = P₂V₂
P₁ = Initial pressure
V₁ = initial volume
P₂ = final pressure
V₂ = final volume
Now we will put the values in formula,
P₁V₁ = P₂V₂
101 KNm⁻² × 180 cm³ = P₂
× 220 cm³
P₂ = 18180 KNm⁻². cm³/220 cm³
P₂ = 82.64 KNm⁻²
The final pressure of gas is 82.64 KNm⁻².
Answer:
Large-scale nuclear is fission a rare phenomenon on Earth because
atoms that undergo fission aren't concentrated enough to sustain a chain reaction.
<h2>Hope it helps you.</h2>
Production of materials and transportation are the examples of three carbon emission.
Extraction and production of purchased materials and transportation of purchased fuels are the examples of three carbon emission. Scope 3 emissions refers to all indirect emissions that occur in the chain of the reporting company that is included in both upstream and downstream emissions.
Big machineries are used for the production and extraction of materials as well as the transportation requires fossil fuels for working which releases carbondioxide gas in the atmosphere so we can conclude that production of materials and transportation are the examples of three carbon emission.
