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Sergio [31]
2 years ago
6

25 pts 3. Compare and contrast a dry cell with a voltaic cell by filling in the table.

Chemistry
1 answer:
Orlov [11]2 years ago
6 0

Answer:

Half Cell  (1)oxidation reaction (2) redox reaction

Anode----(1)and(2) electrochemical cell at which oxidation occurs

Cathode---(1)and(2)electrochemical cell at which reduction

Electrolytes----(1)ammonium chloride------

Oxidation Reaction --- (1)in Anode(2)in Anode

Reduction Reaction----(1)in Cathode(2)in cathode

Bridge---(1)Zinc–carbon battery(2) Galvanic cell

Relative size   ------ (1)smaller--------(2)much larger

Explanation:

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A chemist prepares a solution of barium chloride by measuring out of barium chloride into a volumetric flask and filling the fla
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The given question is incomplete. The complete question is:

A chemist prepares a solution of barium chloride by measuring out 110 g of barium chloride into a 440 ml volumetric flask and filling the flask to the mark with water. Calculate the concentration in mole per liter of the chemist's barium chloride solution. Round your answer to 3 significant digits.

Answer: Concentration of the chemist's barium chloride solution is 1.20 mol/L

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

Molarity=\frac{n\times }{V_s}

where,

n = moles of solute

V_s = volume of solution in L

moles of BaCl_2(solute) = \frac{\text {given mass}}{\text {Molar Mass}}=\frac{110g}{208g/mol}=0.529mol

Now put all the given values in the formula of molality, we get

Molality=\frac{0.529\times 1000}{440ml}=1.20mole/L

Therefore, the molarity of solution is 1.20 mol/L

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<u />

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