Let the initial point of the vector be (x,y). Then the magnitude of the vector v can be written as:

The magnitude of vecor v is given to be 10. So we can write:

Now from the given options, we have to check which one satisfies the above equation. That point will be the initial point of the vector.
The point in option d, satisfies the equation.
Thus, the answer to this question is option D
9514 1404 393
Answer:
f'(x) = (-6x² -14x -23)/(x² +5x +2)²
f''(x) = (12x³ +42x² +138x +202)/(x² +5x +2)³
Step-by-step explanation:
The applicable derivative formula is ...
d(u/v) = (v·du -u·dv)/v²
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f'(x) = ((-x² -5x -2)(4x +4) -(2x² +4x -3)(-2x -5))/(-x² -5x -2)²
f'(x) = (-4x³ -24x²-28x -8 +4x³ +18x² +14x -15)/(x² +5x +2)²
f'(x) = (-6x² -14x -23)/(x² +5x +2)²
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Similarly, the second derivative is the derivative of f'(x).
f''(x) = ((x² +5x +2)²(-12x -14) -(-6x² -14x -23)(2(x² +5x +2)(2x +5)))/(x² +5x +2)⁴
f''(x) = ((x² +5x +2)(-12x -14) +2(6x² +14x +23)(2x +5))/(x² +5x +2)³
f''(x) = (12x³ +42x² +138x +202)/(x² +5x +2)³
Answer:
D
Step-by-step explanation:
Answer:
21
Step-by-step explanation:
To find the mean, add up all the numbers
15+15+25+29 =84
Divide by the number of numbers
84/4 = 21