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3 years ago

7

Write and equation with aa variable on both sides of the equal sign that has infinitely many solutions. solve the equation and e

xplain why it has an infinite number of solutions.

1 answer:

LekaFEV [45]3 years ago

8 0

X = x

to solve, subtract both sides by x:

0 = 0

x is always equals to x so infinite solutions

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4. Find the value of the expression below for r=4 and t=2.

Katen [24]

Answer:

(a) 9

Step-by-step explanation:

$\sf t^3 - r + 20 \div r$

substitute r = 4, t = 2

$\sf (2)^3 - 4 + 20 \div 4$

simplify

$\sf (2)^3 - 4 + 5$

cubic of 2 is 8

$\sf 8 - 4 + 5$

simplify

$\sf 9$

5 0

1 year ago

Read 2 more answers

Can anyone help me???

natita [175]

Answer:

principal (p)=$1300

Interest (I) =$28.67

Time( T) = 1 year

R=?

we have,

R = I*100/T*R

5 0

2 years ago

Will give brainiest algebra 2

mars1129 [50]

The sum of squares of numbers is: 13

Step-by-step explanation:

Let x and y be two numbers

Then,

Difference of the squares of the numbers will be:

$x^2-y^2$

Product will be:

$xy$

Given identity is:

$(x^2+y^2)^2=(x^2-y^2)^2+(2xy)^2$

Given values are:

Difference of the squares of the numbers= $x^2-y^2=5$

Product of numbers = xy = 6

Putting the values in the identity

$(x^2+y^2)^2=(5)^2+[2(6)]^2\\=25+(12)^2\\=25+144\\=169$

As we have to only find x^2+y^2

Taking square root on both sides

$\sqrt{(x^2+y^2)^2}=\sqrt{169}\\x^2+y^2=13$

The sum of squares of numbers is: 13

Keywords: Identities

Learn more about identities at:

#LearnwithBrainly

7 0

3 years ago

Helpppppppppppppppp it is due now

Fudgin [204]

Hey mate hope its help you...

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3 years ago

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A line passes through the points (-6, 4) and (-2, 2). Which is the equation of the line?

cupoosta [38]

Answer:

$\displaystyle y=-\frac{1}{2}x+1$

Step-by-step explanation:

The equation of any line in slope-intercept form is:

y=mx+b

Being m the slope and b the y-intercept.

Assume we know the line passes through points A(x1,y1) and B(x2,y2). The slope can be calculated with the equation:

$\displaystyle m=\frac{y_2-y_1}{x_2-x_1}$

Two points are given: (-6,4) and (-2,2). Calculating the slope:

$\displaystyle m=\frac{2-4}{-2+6}=\frac{-2}{4}=-\frac{1}{2}$

The equation of the line is, so far:

$\displaystyle y=-\frac{1}{2}x+b$

To calculate the value of b, we use any of the given points, for example (-6,4):

$\displaystyle 4=-\frac{1}{2}(-6)+b$

$\displaystyle 4=3+b$

Solving:

b = 1

The equation of the line is:

$\boxed{\displaystyle y=-\frac{1}{2}x+1}$

We can see none of the choices is correct.

8 0

3 years ago