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3 years ago

Application of a biot-savart law

Physics

1 answer:

faltersainse [42]3 years ago

8 0

can be used to determines the expression for magnetic field strength of a current element

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A 1200N load is to be lifted with 200N effort using a first class lever. At what distance

kipiarov [429]

Explanation:

Hey there!!

Let's simply work with it.

Here,

load = 1200N

Effort = 200N

Load distance = 15cm

We have,

According to the principle of lever.

L×LD = E×ED.

1200×15 = 200× ED.

18000 = 200ED.

$ed = \frac{18000}{200}$

Therefore, Effort Distance = 90cm.

Hope it helps....

7 0

3 years ago

A technician attaches one lead of a digital voltmeter to the ground terminal of the TP sensor and the other meter lead to the ne

wariber [46]

Answer:

Neither A or B

Explanation:

The 37.3mv is not the signal voltage

sensor ground circuit does not has excessive resistance.

5 0

3 years ago

Blood is accelerated from rest to 30.0 cm/s in a distance of 1.80 cm by the left ventricle of the heart. (a) Make a sketch of th

Mila [183]

Answer:

a. Picture attached

b. V, X

c. $t=0.12 s$

d. It makes sense cosidering that a normal heart beat rate is between 60 and 100 beats per minute (bpm).

Explanation:

First we have to identify the unknown of this problem:

$a: acceleration\\t: time$

Considering the characteristics of the problem and that distance and velocity are specified, the acceleration is constant, for that reason we use the equations of uniformly accelerated motion as follows:

$v=v_{0}+at\\ x=x_{0}+ v_{0}+\frac{1}{2}at^{2}$

If we reorganize the equations, considering that $x_{0}$ and $v_{0}$ are zero because motion starts from rest , we have:

$a=\frac{v}{t} \\x=\frac{1}{2}at^{2} =\frac{1}{2}\frac{v}{t} t^{2}=\frac{1}{2} vt\\t=\frac{2x}{v} \\t=\frac{2*1.80cm}{30.0\frac{cm}{s} } \\t=0.12 s$

Finally, the analysis of the result leaves us to understand why the normal heart beat rate varies between 60 and 100 bpm.

6 0

3 years ago

Visible light transmitting through a certain medium.

Verizon [17]

I think its A: Translucent hope this helps if I'm wrong I'm sorry

8 0

3 years ago

A conductor carrying a conventional current in the positive-x direction is in a magnetic field whose vector points in the positi

a_sh-v [17]

Answer:

Positive Z direction (out of screen)

Explanation:

Magnetic force is given by $F = il \wedge B$ . A quick way to gauge the components is to put your left middle finger on the direction of the current, your index on the direction of the magnetic field, and the thumb gives you the answer you want.

4 0

3 years ago

Read 2 more answers