Answer: 5.30m
Explanation:
depth of pool = 3.2 m
i = 67.75°
Using snell's law, we have,
n₁ × sin(i) = n₂ × 2 × sin(r)
n₁ = 1, n₂ =1.33, r= 44.09°
Hence,
Distance of Google from edge if pool is:
2.2 + d×tan(r) = 2.2 + (3.2 × tan(44.09°) =5.30m
Answer:
The rate at which the container is losing water is 0.0006418 g/s.
Explanation:
- Under the assumption that the can is a closed system, the conservation law applied to the system would be:
, where
is all energy entering the system,
is the total energy leaving the system and,
is the change of energy of the system. - As the purpose is to kept the beverage can at constant temperature, the change of energy (
) would be 0. - The energy that goes into the system, is the heat transfer by radiation from the environment to the top and side surfaces of the can. This kind of transfer is described by:
where
is the emissivity of the surface,
known as the Stefan–Boltzmann constant,
is the total area of the exposed surface,
is the temperature of the surface in Kelvin,
is the environment temperature in Kelvin. - For the can the surface area would be ta sum of the top and the sides. The area of the top would be
, the area of the sides would be
. Then the total area would be 
- Then the radiation heat transferred to the can would be
. - The can would lost heat evaporating water, in this case would be
, where
is the rate of mass of water evaporated and,
is the heat of vaporization of the water (
). - Then in the conservation balance:
, it would be
. - Recall that
, then solving for
:
Answer:
Natae Si Jordan Kaya Sya Napaihe
Explanation:
haha
Maybe around 350 years, depending on the carbon cycle and the time taken through steps.
Answer:
Now since mass of reactant is equal to mass of the product after the reaction so we can say that mass conservation is applicable here
Explanation:
As we know that zinc reacts with copper sulfate
so the reaction is given as

so here we have




Now total mass of reactant is given as

Mass of the product is given as

Now since mass of reactant is equal to mass of the product after the reaction so we can say that mass conservation is applicable here