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11111nata11111 [884]
3 years ago
10

Which behavior is not true for incident rays striking a concave mirror? a. incident rays parallel to the principal axis are refl

ected to the focus
b. incident rays passing through the focus are reflected parallel to the principal axis
c. incident rays passing through the center are reflected back to the center.
d. incident rays from an object at infinity and parallel to the principal axis are reflected to the center.
Physics
1 answer:
mel-nik [20]3 years ago
8 0

Answer:

Option (D)

Explanation:

a concave mirror is called a converging mirror, because when the rays of light falls on it, it converges the path of rays of light falling on it after reflection.

When the rays from the object at infinity and parallel to the principal axis, then after reflection they passes form the focus of the mirror.

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Can someone pleaseeee answer this !!!!!!
LenaWriter [7]

Answer:

The person with locked legs will experience greater impact force.

Explanation:

Let the two persons be of nearly equal mass (say m)

The final velocity of an object (person) dropped from a height H (here 2 meters) is given by,

v=\sqrt{2gH}

(g = acceleration due to gravity)

which can be derived from Newton's equation of motion,

v^2=u^2+2aS

Now, the time taken (say t ) for the momentum ( mv ) to change to zero will be more in the case of the person who bends his legs on impact than who keeps his legs locked.

We know that,

Force=\frac{\Delta(mv)}{t}

Naturally, the person who bends his legs will experience lesser force since t is larger.

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2 years ago
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BlackZzzverrR [31]

Explanation:

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2 years ago
A motorcycle starting from rest covers 200 metre distance in 6 second. Calculate final velocity and acceleration of the motorcyc
QveST [7]

Answer:

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2 years ago
How is displacement different from distance?
Anni [7]

Answer:

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Explanation:

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5 0
3 years ago
Read 2 more answers
An airplane flies at 40 m/s at an altitude of 50 meters. The pilot drops a heavy package which falls to the ground. Where, appro
igor_vitrenko [27]

Answer:

128 m

Explanation:

From the question given above, the following data were obtained:

Horizontal velocity (u) = 40 m/s

Height (h) = 50 m

Acceleration due to gravity (g) = 9.8 m/s²

Horizontal distance (s) =?

Next, we shall determine the time taken for the package to get to the ground.

This can be obtained as follow:

Height (h) = 50 m

Acceleration due to gravity (g) = 9.8 m/s²

Time (t) =?

h = ½gt²

50 = ½ × 9.8 × t²

50 = 4.9 × t²

Divide both side by 4.9

t² = 50 / 4.9

t² = 10.2

Take the square root of both side

t = √10.2

t = 3.2 s

Finally, we shall determine where the package lands by calculating the horizontal distance travelled by the package after being dropped from the plane. This can be obtained as follow:

Horizontal velocity (u) = 40 m/s

Time (t) = 3.2 s

Horizontal distance (s) =?

s = ut

s = 40 × 3.2

s = 128 m

Therefore, the package will land at 128 m relative to the plane

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2 years ago
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