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Artyom0805 [142]
2 years ago
10

A gymnast of mass 62.0 kg hangs from a vertical rope attached to the ceiling. You can ignore the weight of the rope and assume t

hat the rope does not stretch. Use the value 9.81m/s2 for the acceleration of gravity. Calculate the tension T in the rope if the gymnast hangs motionless on the rope.Calculate the tension T in the rope if the gymnast climbs the rope at a constant rate.Calculate the tension T in the rope if the gymnast climbs up the rope with an upward acceleration of magnitude 1.20m/s2 .Calculate the tension T in the rope if the gymnast slides down the rope with a downward acceleration of magnitude 1.20m/s2 .*all answers in Newtons
Physics
1 answer:
MrRissso [65]2 years ago
5 0

Answer:

a) T = 608.22 N

b) T = 608.22 N

c) T = 682.62 N

d) T = 533.82 N

Explanation:

Given that the mass of gymnast is m = 62.0 kg

Acceleration due to gravity is g = 9.81 m/s²

Thus; The weight of the gymnast is acting downwards and tension in the string acting upwards.

So;

To calculate the tension T in the rope if the gymnast hangs motionless on the rope; we have;

T = mg

= (62.0 kg)(9.81 m/s²)

= 608.22 N

When the gymnast climbs the rope at a constant rate tension in the string is

= (62.0 kg)(9.81 m/s²)

= 608.22 N

When the gymnast climbs up the rope with an upward acceleration of magnitude

a = 1.2 m/s²

the tension in the string is  T - mg = ma (Since acceleration a is upwards)

T = ma + mg

= m (a + g )

= (62.0 kg)(9.81 m/s² + 1.2  m/s²)

= (62.0 kg) (11.01 m/s²)

= 682.62 N

When the gymnast climbs up the rope with an downward acceleration of magnitude

a = 1.2 m/s² the tension in the string is  mg - T = ma (Since acceleration a is downwards)

T = mg - ma

= m (g - a )

= (62.0 kg)(9.81 m/s² - 1.2 m/s²)

= (62.0 kg)(8.61 m/s²)

= 533.82 N

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Perform the following calculations and give your answer with the correct number of significant figures
love history [14]

Answer:

see below

Explanation:

a. 0.1886 x 12 =2.2632

This has 2 sig figures so the answer can only have 2 sig figures

2.3

b. 2.995 - 0.16685 =2.82815

The most accurate in the problem is to thousands place so our answer can only be accurate to the thousands place

2.828

c. 910 x 0.18945=172.3995

The  least number of significant figures is 3 so the answer can only have 3 significant figures

172

3 0
2 years ago
Student 1 lifts a box with a force of 500 N and sets it on a tabletop 1.2 m high. Student 2 pushes an identical box up a 5 m ram
Troyanec [42]

The student who did the most work is student 2 with 2500 Joules.

<u>Given the following data:</u>

  • Force 1 = 500 Newton
  • Distance 1 = 1.2 meter
  • Force 2 = 500 Newton
  • Distance 2 = 5 meter

To determine which of the students did the most work:

Mathematically, the work done by an object is given by the formula;

Work\;done = Force \times distance

<u>For </u><u>student 1</u><u>:</u>

Work\;done = 500 \times 1.2

Work done = 600 Joules

<u>For </u><u>student 2</u><u>:</u>

Work\;done = 500 \times 5

Work done = 2500 Joules.

Therefore, the student who did the most work is student 2 with 2500 Joules.

Read more: Read more: brainly.com/question/13818347

7 0
2 years ago
Read 2 more answers
Simple Pendulum: A 34-kg child on an 18-kg swing set swings back and forth through small angles. If the length of the very light
SIZIF [17.4K]

Answer:

The correct answer is "4.443 sec".

Explanation:

Given:

Mass of child,

= 34 kg

Mass of swing,

= 18 kg

Length,

= 4.9 m

The time period of pendulum will be:

T = 2 \pi \sqrt{4g}

  = 2 \pi \sqrt{\frac{4.9}{9.8} }

  = 4.443 \ sec  

5 0
3 years ago
Read 2 more answers
If a substance can be separated by physical means and it is not the same throughout, what is it.
VMariaS [17]

Answer:

The answer is Heterogeneous (B) I did the lesson and took the quiz today.

Explanation:

3 0
3 years ago
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The general kinematic equations of motion for vertical displacement can also be simplified significantly. Write the simplified
Setler [38]

Answer:

Δy = v₀t + (1/2)gt²

where g = 9.81 m/s if the body is moving downwards and g = -9.81 m/s if the body is moving upwards

Explanation:

The general kinematic equation for horizontal displacement is gives as:

Δx = v₀t + (1/2)at²

Where

Δx = change in the x direction

v₀ = initial velocity

t = time

a = acceleration

If the body is vertically instead of horizontally, Δx is changed to Δy

Δy = v₀t + (1/2)at²

For a vertical moving body, the acceleration it experiences is the gravitational accerelation of the earth 'g'

So the equation becomes:

Δy = v₀t + (1/2)gt²

where g = 9.81 m/s if the body is moving downwards and g = -9.81 m/s if the body is moving upwards

4 0
3 years ago
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