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Stels [109]
3 years ago
9

5 over 33 divided by 7 over 22

Mathematics
2 answers:
hichkok12 [17]3 years ago
3 0

Answer:

110/231=10/21

Step-by-step explanation:

solmaris [256]3 years ago
3 0

Answer:

10 over 21 (10/21)

Step-by-step explanation:

First, multiply the numerators and the denominators.

Numerators= 5 • 22= 110

Denominators= 33 • 7= 231

Then, that will come out to be 110 over 231 (110/231)

Next, find the greatest common factor of 110 and 231, which is 11, and divide both 110 and 231 by 11.

Finally, 110 divided by 11 is 10, and 231 divided by 11 is 21, so, the equation comes out to be 5 over 33 divided by 7 over 22. (5/33 divided by 7/22)

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Andrew [12]

Answer:

Step-by-step explanation:

Given that a box contains 45 light bulbs, of which 36 are good and the other 9 are defective.

Probability for any one to be defective as of now is \frac{36}{45} =0.80

a) P(E) = 0.80

b) After I draw we have 35 good ones and 9 defective

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c) P(G/EF)

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Once I and ii are good we have 43 bulbs with 34 good ones

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VladimirAG [237]
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3 years ago
JKL is a straight line.
kirza4 [7]

Answer:

x = 32°

Step-by-step explanation:

∆KLM is an isosceles triangle because it has two equal sides, KL & KM. Therefore, the angles opposite to each of the two equal sides, which are referred to as the base angles are congruent to each other.

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The only side that they have the same is B-E.

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