Answer:
The company should take a sample of 148 boxes.
Step-by-step explanation:
Hello!
The cable TV company whats to know what sample size to take to estimate the proportion/percentage of cable boxes in use during an evening hour.
They estimated a "pilot" proportion of p'=0.20
And using a 90% confidence level the CI should have a margin of error of 2% (0.02).
The CI for the population proportion is made using an approximation of the standard normal distribution, and its structure is "point estimation" ± "margin of error"
[p' ± ]
Where
p' is the sample proportion/point estimator of the population proportion
is the margin of error (d) of the confidence interval.
So
n= 147.28 ≅ 148 boxes.
I hope it helps!
It's just like multiplying and dividing a negative, such as -1 *2=-2 and -2 / 1= -1
if there is one negative then it will be negative, so in this case it will be -7 / 2=
answer= -3 1/2
46/69 * 100
0.66666*100
which is 66percent
Answer:
d is your answer
Step-by-step explanation:
Answer:
x = 7
Step-by-step explanation:
4x+5x=63
Combine like terms
9x = 63
Divide by 9
9x/9 =63/9
x = 7