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Maurinko [17]
3 years ago
7

The molarity of a solution of 5.0 g of kcl in 100. ml of solution is ________.

Chemistry
2 answers:
Sliva [168]3 years ago
8 0

<u>Answer:</u> The molarity of solution is 0.67 M

<u>Explanation:</u>

To calculate the molarity of solution, we use the equation:

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}

We are given:

Mass of solute (KCl) = 5.0 g

Molar mass of potassium chloride = 74.55 g/mol

Volume of solution = 100 mL

Putting values in above equation, we get:

\text{Molarity of solution}=\frac{5g\times 1000}{74.55g/mol\times 100mL}\\\\\text{Molarity of solution}=0.67M

Hence, the molarity of solution is 0.67 M

sdas [7]3 years ago
7 0
Molarity is defined as the number of moles of solute in 1 L of solution 
mass fo KCl in the solution is - 5.0 g
number of moles of KCl - 5.0 g/ 74.5 g/mol  = 0.067 mol
number of moles of KCl in 100 mL - 0.067 mol
therefore number of KCl moles in 1 L - 0.067 / 100 mL x 1000 mL = 0.67 M
molarity of KCl is 0.67 M
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99.9224 % of the acid is not ionized.

____HA + H₂O ⇌ A⁻ + H₃O⁺

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Hope this Helps!!!

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