Question

Be sure to answer all parts. an aqueous solution of a strong base has a ph of 10. 220 at 25°c. calculate the concentration of the base if the base is (a) lioh: × 10 m (b) ba(oh)2: × 10 m

Answer 1

An aqueous solution of a strong base has a pH of 10. 220 at 25°C then concentration of the base if the base is

(a)  LiOH =  1.66×$10^{-4}$  M

(b)  $Ba(OH)_{2$ =  3.32×$10^{-4}$M

Calculation ,

For calculation of concentration of the   LiOH and  $Ba(OH)_{2$ first we have to calculate pOH of the solution.

pH + pOH = 14

pOH = 14 - pOH = 14 - 10.22  = 3.78

pOH = -㏒ [ $OH^{-}$ ]

[ $OH^{-}$ ] = $10^{-pH}$ =  $10^{-3.78}$ = 1.66×$10^{-4}$

So ,  concentration of the base LiOH =  1.66×$10^{-4}$

So ,  concentration of the base $Ba(OH)_{2$ =  1.66×$10^{-4}$ ×2 = 3.32×$10^{-4}$

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