An aqueous solution of a strong base has a pH of 10. 220 at 25°C then concentration of the base if the base is
(a) LiOH = 1.66×
M
(b)
= 3.32×
M
Calculation ,
For calculation of concentration of the LiOH and
first we have to calculate pOH of the solution.
pH + pOH = 14
pOH = 14 - pOH = 14 - 10.22 = 3.78
pOH = -㏒ [
]
[
] =
=
= 1.66×
So , concentration of the base LiOH = 1.66×
So , concentration of the base
= 1.66×
×2 = 3.32×
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