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Misha Larkins [42]
3 years ago
14

Consider two equal-volume balloons under the same conditions of temperature and pressure. One contains helium, and the other con

tains carbon dioxide.
Which of the following are the SAME for these two gas samples. Select all choices that apply.

Number of gas particles (atoms or molecules)

Density

Number of moles of gas

Average kinetic energy

Average particle velocity

Mass
Chemistry
1 answer:
Olegator [25]3 years ago
5 0

Answer:

1. Number of gas particles (atoms or molecules)

2. Number of moles of gas

3. Average kinetic energy

Explanation:

Since the two gas has the same volume and are under the same conditions of temperature and pressure,

Then:

1. They have the same number of mole because 1 mole of any gas at stp occupies 22.4L. Now both gas will occupy the same volume because they have the same number of mole

2. Since they have the same number of mole, then they both contain the same number of molecules as explained by Avogadro's hypothesis which states that at the same temperature and pressure, 1 mole of any substance contains 6.02x10^23 molecules or atoms.

3. Being under the same conditions of temperature and pressure, they both have the same average kinetic energy. The kinetic energy of gas is directly proportional to the temperature. Now that both gas are under same temperature, their average kinetic energy are the same.

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Minchanka [31]

Answer:

147 g

Explanation:

<em>The number of moles of a substance is the ratio of the mass of the substance and the molar mass of that substance.</em> Mathematically,

  mole = mass of substance/molar mass

In this case, Nick needs 3.5 moles of NaF, the molar mass of NaF is calculated as:

  23 + 19 = 42 g/mol (Note: Na = 23, F = 19)

Hence,

mass of 3.5 mole NaF = mole x molar mass

                              = 3.5 x 42 = 147 g.

<em>Hence, Nick would need to measure out </em><em>147 g</em><em> NaF using a suitable weighing balance.</em>

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3 years ago
At a constant temperature, 600 mL of an ideal gas is at a pressure of 760 mmHg . If the volume is decreased to 300 mL, the press
belka [17]

Answer:

1520mmHg

Explanation:

Data obtained from the question include:

V1 (initial volume) = 600 mL

P1 (initial pressure) = 760 mmHg

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Using the Boyle's law equation P1V1 = P2V2, the final pressure of the gas can easily be obtained as shown below:

P1V1 = P2V2

760 x 600 = P2 x 300

Divide both side by 300

P2 = (760 x 600) /300

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The final pressure of the gas is 1520mmHg

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these answers can be searched in Google

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