Answer:
147 g
Explanation:
<em>The number of moles of a substance is the ratio of the mass of the substance and the molar mass of that substance.</em> Mathematically,
mole = mass of substance/molar mass
In this case, Nick needs 3.5 moles of NaF, the molar mass of NaF is calculated as:
23 + 19 = 42 g/mol (Note: Na = 23, F = 19)
Hence,
mass of 3.5 mole NaF = mole x molar mass
= 3.5 x 42 = 147 g.
<em>Hence, Nick would need to measure out </em><em>147 g</em><em> NaF using a suitable weighing balance.</em>
Answer:
1520mmHg
Explanation:
Data obtained from the question include:
V1 (initial volume) = 600 mL
P1 (initial pressure) = 760 mmHg
V2 (final volume) = 300 mL
P2 (final pressure) =.?
Using the Boyle's law equation P1V1 = P2V2, the final pressure of the gas can easily be obtained as shown below:
P1V1 = P2V2
760 x 600 = P2 x 300
Divide both side by 300
P2 = (760 x 600) /300
P2 = 1520mmHg
The final pressure of the gas is 1520mmHg
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As we can see the chemical equation is balanced.K3PO4 + Al(NO3)3 → 3KNO3 + AlPO4
So, by principle of conservation of mass when 1 mole of K3PO4 reacts with 1 mol of Al(NO3)3 , it peoduces 3 mol of KNO3 and 1 mol of AlPO4
So, when 2.5 moles of potassium phosphate react and Al(NO3)3 is present in excess , 2.5*3= 7.5 mol of KNO3 is formed
D.) It depends cuz no yeild is 100%..I mean side reactions also occur in most of the reactions. So mass of the reactant is not equal to the mass of the product. Hope it helps