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Misha Larkins [42]
3 years ago
14

Consider two equal-volume balloons under the same conditions of temperature and pressure. One contains helium, and the other con

tains carbon dioxide.
Which of the following are the SAME for these two gas samples. Select all choices that apply.

Number of gas particles (atoms or molecules)

Density

Number of moles of gas

Average kinetic energy

Average particle velocity

Mass
Chemistry
1 answer:
Olegator [25]3 years ago
5 0

Answer:

1. Number of gas particles (atoms or molecules)

2. Number of moles of gas

3. Average kinetic energy

Explanation:

Since the two gas has the same volume and are under the same conditions of temperature and pressure,

Then:

1. They have the same number of mole because 1 mole of any gas at stp occupies 22.4L. Now both gas will occupy the same volume because they have the same number of mole

2. Since they have the same number of mole, then they both contain the same number of molecules as explained by Avogadro's hypothesis which states that at the same temperature and pressure, 1 mole of any substance contains 6.02x10^23 molecules or atoms.

3. Being under the same conditions of temperature and pressure, they both have the same average kinetic energy. The kinetic energy of gas is directly proportional to the temperature. Now that both gas are under same temperature, their average kinetic energy are the same.

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How many grams of Kr are in a 9.59 L cylinder at 46.0 'C and 4.62 atm?<br> mass:
Sladkaya [172]

Answer:

Mass = 141.6 g

Explanation:

Given data:

Mass of Kr in gram =  ?

Volume in L = 9.59 L

Temperature = 46.0°C

Pressure = 4.62 atm

Solution:

The given problem will be solve by using general gas equation,

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

Now we will convert the temperature.

46.0+273 = 319 K

4.62 atm × 9.59 L = n× 0.0821 atm.L/ mol.K  ×319 K

44.3 atm.L = n×26.19 atm.L/ mol

n = 44.3 atm.L / 26.19 atm.L/ mol

n = 1.69 mol

Mass in gram:

Mass = number of moles × molar mass

Mass = 1.69 mol × 83.79 g/mol

Mass = 141.6 g

8 0
3 years ago
Is the element Americium a metal, metalloid, or a nonmetal?
MaRussiya [10]
Americium is a metal.
6 0
3 years ago
Read 2 more answers
A football field is 120 yards by 53.333 yards. What is the area of the football field in acres if 1 acre=43560 ft?? Use correct
maw [93]

Answer:

1.3223 acres

Explanation:

a football field's area is 360 feet (120 yards) x 160 feet (53.333 yards) = 57,600 sq. feet

if the area of an acre is 43,560 sq. feet, then a football field in acres = 57,600 sq. feet / 43,560 sq. feet = 1.3223 acres

we can verify our answer by doing the same calculation in sq. yards:

football field = 120 yards x 53.33 yards = 6,400 sq. yards

an acre is 4,840 sq. yards

football field in acres = 6,400 sq. yards / 4,840 sq. yards = 1.3223 acres

8 0
3 years ago
Read 2 more answers
Why is climate change a concern when it comes to animal behavior and ability to reproduce
kow [346]

Answer:

hope this helps! :)

Explanation:

While humans and many other animals determine sex genetically, many reptiles and some fish use the incubation temperature of the eggs to set the gender of their offspring. This means that changing global temperatures could alter the ratio of sexes produced, making it harder for these animals to find mates

4 0
3 years ago
Which solution will form a precipitate when mixed with a solution of aqueous na2co3? which solution will form a precipitate when
trapecia [35]

Answer:

CuCl_{2}(aq.) will form a precipitate of insoluble CuCO_{3} when aqueous Na_{2}CO_{3} is added.

Explanation:

According to solubility rule-

all carbonates are insoluble except group IA compounds and NH_{4}^{+}

all salts of sodium are soluble

When Na_{2}CO_{3} is added to given solutions, a double displacement reaction takes place in each solution to form a sodium salt and a carbonate salt.

So, in accordance with solubility rule, addition of Na_{2}CO_{3} into CuCl_{2}(aq.) will result precipitation of insoluble CuCO_{3}

Reaction: Na_{2}CO_{3}(aq.)+CuCl_{2}(aq.)\rightarrow 2NaCl(aq.)+CuCO_{3}(aq.)

4 0
3 years ago
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