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MArishka [77]
3 years ago
6

Pleaseeeeeeee help me

Mathematics
2 answers:
tino4ka555 [31]3 years ago
7 0

Answer:

x = 24

Step-by-step explanation:

10:8

10(3) = x(3)

x = 8

30 : 24

Liula [17]3 years ago
7 0
The answer to this equation is 24
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harina [27]
1 and 2, 3 und 5, etc

5 0
3 years ago
The sum of the first three terms of an arithmetic sequence is 108, and the sum of the next three terms is 183. what is the value
qaws [65]
The key is to find the first term a(1) and the difference d.

in an arithmetic sequence, the nth term is the first term +(n-1)d
the firs three terms: a(1), a(1)+d, a(1)+2d
the next three terms: a(1)+3d, a(1)+4d, a(1)+5d,
a(1) + a(1)+d +a(1)+2d=108
a(1)+3d + a(1)+4d + a(1)+5d=183

subtract the first equation from the second equation: 9d=75, d=75/9=25/3
Plug d=25/3 in the first equation to find a(1): a(1)=83/3

the 11th term is: a(1)+(25/3)(11-1)=83/3 +250/3=111

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4 0
3 years ago
HELP ASAP. Dilation scale=2, center (5,4) <br> Graph the new points
frosja888 [35]

Answer:

3.5

Step-by-step explanation:

5 0
2 years ago
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gregori [183]

Answer:

8

Step-by-step explanation:

7 0
3 years ago
There are 200 students in the 8th grade class at Alleghany Middle School. Of these students, 8% play basketball and 14% play soc
sergeinik [125]

Answer:

The probability that a student plays either basketball or soccer is 19% or 0.19.

Step-by-step explanation:

Let A be the event that student play basketball and  B be the event that student play soccer.

P(A)=8\%

P(B)=14\%

It is given that 6 students play on both teams.

P(A\cap B)=\frac{6}{200}\times 100=3\%

We have to find the probability that a student plays either basketball or soccer.

P(A\cup B)=P(A)+P(B)-(A\cap B)

P(A\cup B)=8\%+14\%-3\%

P(A\cup B)=19\%

Therefore the probability that a student plays either basketball or soccer is 19% or 0.19.

6 0
4 years ago
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