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3 years ago

Quadrilateral TRPK ~ Quadrilateral EWMN Which statements are correct? Select all that apply. Question 8 options:

1 answer:

8 0

For starters, we know that the angle measures have to be similar or the same, since similar shapes always contain the same angle measures. We can use the way that the letters of each shape line up to identify which angle correspond to each other. Angle R should be congruent to angle W, but angle P is not congruent to N, it would be congruent to M though. Now we get to the tricky part, figuring out line segment lengths. Again using the letters in each shape, we can see that TK and NM do not correspond to each other, and thus cannot be congruent or similar. But, with RP/WM, this is correctly lined up with each other. TR/EW, same with this one, and TK/EN is also the same. With this Info, we can figure out the dilation of the smaller shape, or just figure out if they are similar or not. (So pick B. And D.)

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Read 2 more answers

A data set includes 103 body temperatures of healthy adult humans having a mean of 98.1 F and a standard deviation of 0.56 F. Co

Ira Lisetskai [31]

Answer:

The 99% confidence interval estimate of the mean body temperature of all healthy humans is (97.955F, 98.245F).

98.6F is above the upper end of the interval, which means that the sample suggests that the mean body temperature could be lower than 98.6F.

Step-by-step explanation:

The first step is finding the confidence interval

The sample size is 103.

The first step to solve this problem is finding how many degrees of freedom there are, that is, the sample size subtracted by 1. So

$df = 103-1 = 102$

Then, we need to subtract one by the confidence level $\alpha$ and divide by 2. So:

$\frac{1-0.99}{2} = \frac{0.01}{2} = 0.005$

Now, we need our answers from both steps above to find a value T in the t-distribution table. So, with 102 and 0.005 in the t-distribution table, we have $T = 2.63$ .

Now, we need to find the standard deviation of the sample. That is:

$s = \frac{0.56}{\sqrt{103}} = 0.055$

Now, we multiply T and s

$M = T*s = 2.63*0.055 = 0.145$

For the lower end of the interval, we subtract the mean by M. So 98.1 - 0.145 = 97.955F.

For the upper end of the interval, we add the mean to M. So 98.1 + 0.145 = 98.245F.

The 99% confidence interval estimate of the mean body temperature of all healthy humans is (97.955F, 98.245F).

98.6F is above the upper end of the interval, which means that the sample suggests that the mean body temperature could be lower than 98.6F.

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3 years ago

If ☆ x 2 = 0, then ☆ 8 will equal: 0 + 6 O + 8 0 x 2 O X4 0 x 8

soldier1979 [14.2K]

The last one I think

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