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2 years ago

There is a frog jumping contest in Hippity Hop County. Leaping Larry jumps 18cm every 6 seconds.

Mathematics

1 answer:

wel2 years ago

6 0

Leaping Larry jumps 180 cm every 1 min
Bouncing Billy jumps 140 cm every 1 min

180 - 140 = 40 cm difference

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The Powerball lottery is open to participants across several states. When entering the powerball lottery, a participant selects

mr Goodwill [35]

Answer and Step-by-step explanation:

Number of ways = 59C5 × 35= 59!/(54!*5!)* 35= 175223510

Odds are thus 1 in 175223510

b) 1 million - Number of ways = 59!/(54!*5!) =5006386*35/34 = 5153632

Odds are thus 1 in 5153632

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3 years ago

Whats the answer giving brainliest>>>>

Elza [17]

Answer:

the answer is b

Step-by-step explanation:

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2 years ago

What is the best first step in solving the equation 3 +<img src="https://tex.z-dn.net/?f=3%5Csqrt%5B6%5D%7Bx%7D" id="TexFormula1

Andreas93 [3]

$3+3\sqrt[6]{x}~~ = ~~5\implies \stackrel{\textit{1st step,-3 to both sides}}{3\sqrt[6]{x}~~ = ~~2}\implies \sqrt[6]{x}=\cfrac{2}{3} \\\\\\ (\sqrt[6]{x})^6=\left( \cfrac{2}{3} \right)^6\implies x=\cfrac{2^6}{3^6}\implies x=\cfrac{64}{729}$

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1 year ago

Plz help i just dont get and plz do not put a file its annoying

8090 [49]

Answer:

Hello! Your answer would be, BELOW!

Step-by-step explanation:

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2 years ago

Can someone please help me with my maths question

DIA [1.3K]

Answer:

$a. \ \dfrac{625 \cdot m}{27 \cdot n^{11}}$

$b. \ \dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}$

Step-by-step explanation:

The question relates with rules of indices

(a) The give expression is presented as follows;

$\dfrac{m^3 \times \left (n^{-2} \right )^4 \times (5 \cdot m)^4}{\left (3 \cdot m^2 \cdot n \right )^3}$

By expanding the expression, we get;

$\dfrac{m^3 \times n^{-8} \times 5^4 \times m^4}{\left 3^3 \times m^6 \times n^3}$

Collecting like terms gives;

$\dfrac{m^{(3 + 4 - 6)} \times 5^4}{ 3^3 \times n^{3 + 8}} = \dfrac{625 \cdot m}{27 \cdot n^{11}}$

$\dfrac{m^3 \times \left (n^{-2} \right )^4 \times (5 \cdot m)^4}{\left (3 \cdot m^2 \cdot n \right )^3}= \dfrac{625 \cdot m}{27 \cdot n^{11}}$

(b) The given expression is presented as follows;

$x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \div (x \cdot y^n)^4$

Therefore, we get;

$x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \times x^{-4} \times y^{-4 \cdot n}$

Collecting like terms gives;

$x^{3 \cdot m + 2 - 4} \times \left (y^{3 \cdot n - 3 -4 \cdot n}} \right ) = x^{3 \cdot m - 2} \times \left (y^{ - 3 -n}} \right ) = x^{3 \cdot m - 2} \div \left (y^{ 3 + n}} \right )$

$x^{3 \cdot m - 2} \div \left (y^{ 3 + n}} \right ) = \dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}$

$x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \times x^{-4} \times y^{-4 \cdot n} =\dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}$

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2 years ago