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Inessa [10]
3 years ago
13

In Detroit the high temperature in degrees Fahrenheit for five days in January were -12 , -8 , -3 , 6 , -15. What was the averag

e temperature for these five days?
Mathematics
2 answers:
Marianna [84]3 years ago
3 0

Average temperature = (12 - 8 + 3 + 6 - 15) / 5 = -2/5 = -0.4

Vitek1552 [10]3 years ago
3 0
The average temperature is - 0.4
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Answer:

Enter the value of the score in the laboratory 1

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Laboratory Average = (L1 + L2 + L3) / 3

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Print "Test Average"

Course qualification = 0.55 * (Laboratory Average) + 0.45 * (Test Average)

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Step-by-step explanation:

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Prime number between 60 and 80 with the 10’s digit being one less than the 1st digit
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A health statistics agency in a certain country tracks the number of adults who have health insurance. Suppose according to the
Nana76 [90]

Answer:

a) There is a 15.3% probability that a randomly selected person in this country is 65 or older.

b) Given that a person in this country is uninsured, there is a 2.2% probability that the person is 65 or older.

Step-by-step explanation:

We have these following percentages:

5.3% of those under the age of 18, 12.6% of those ages 18–64, and 1.3% of those 65 and older do not have health insurance.

22.6% of people in the county are under age 18, and 62.1% are ages 18–64.

(a) What is the probability that a randomly selected person in this country is 65 or older?

22.6% are under 18

62.10% are 18-64

The rest are above 65

So

100% - (22.6% + 62.10%) = 15.3%

There is a 15.3% probability that a randomly selected person in this country is 65 or older.

b) Given that a person in this country is uninsured, what is the probability that the person is 65 or older?

This can be formulated as the following problem:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

P = \frac{P(B).P(A/B)}{P(A)}

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

So, what is the probability that a person is 65 and older, given that the person is uninsured.

P(B) is the probability that a person is 65 and older. From a), we have that P(B) = 0.153

P(A/B) is the probability is uninsured, given that that person is 65 and older. So P(A/B) = 0.013

P(A) is the probability that a person is uninsured. That is the sum of 5.3% of 22.6%, 12.6% of 62.1% and 1.3% of 15.3%. So:

P(A) = 0.053*(0.226) + 0.126*(0.621) + 0.013*(0.153) = 0.0922

So

P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.153*0.013}{0.0922} = 0.022

Given that a person in this country is uninsured, there is a 2.2% probability that the person is 65 or older.

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2 years ago
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