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yuradex [85]
3 years ago
7

A road map has a scale of 5 cm = 1 km. If two towns are actually 15.5 km apart, how far apart are they on the map scale?

Mathematics
1 answer:
tatiyna3 years ago
5 0

Answer:

77.5 cm

Step-by-step explanation:

15.5km* 5 cm on map/ 1 actual km= so 77.5 cm

if my answer helps please mark as brainliest.

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Sadie wants to paint 2 boxes. The paint costs $0.02 cents per square cm. If she throws the lids away, how much will it cost to p
Alex

Answer:

how many square centimeters is the box??

Step-by-step explanation:

8 0
3 years ago
Please help me with #14 and #15
RSB [31]
What is 14 and 15 tell me 
6 0
3 years ago
The proof that ΔACB ≅ ΔECD is shown. Given: AE and DB bisect each other at C. Prove: ΔACB ≅ ΔECD What is the missing statement i
GarryVolchara [31]

Answer:

The missing statement is ∠ACB ≅ ∠ECD

Step-by-step explanation:

Given two lines segment AC and BD bisect each other at C.

We have to prove that ΔACB ≅ ΔECD

In triangle ACB and ECD

AC=CE    (Given)

BC=CD   (Given)

Now to prove above two triangles congruent we need one more side or angle

so, as seen in options the angle ∠ACB ≅ ∠ECD due to vertically opposite angles

hence, the missing statement is ∠ACB ≅ ∠ECD


9 0
3 years ago
Read 2 more answers
What is the value of x?​
WINSTONCH [101]

Answer:

\large\boxed{x=8\sqrt2}

Step-by-step explanation:

\bold{METHOD\ 1}\\\\\text{Use the Pythagorean theorem:}\\\\leg^2+leg^2=hypotenuse^2\\\\\text{We have}\ leg=8,\ leg=8,\ hypotenuse=x.\\\text{Substitute:}\\\\x^2=8^2+8^2\\\\x^2=2(8^2)\to x=\sqrt{2(8^2)}\qquad\text{use}\ \sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\\\\x=\sqrt2\cdot\sqrt{8^2}\qquad\text{use}\ \sqrt{a^2}=a\\\\x=8\sqrt2

\bold{METHOD\ 2}\\(look\ at\ the\ picture)\\\\\text{We have}\ a=8.\ \text{Therefore}\ a\sqrt2=8\sqrt2

5 0
3 years ago
Please help. !!!!!!!!
Kryger [21]
Basically you find the data points and fill in the values. For Point J it is (2,4). They want you to do this: (2-4,4-6)...it then becomes (-2,-2).
So 
J: (-2,-2)
K: (-1, -4)
I: (-2, -5)
Those are your new points. I hope this helps love! :)
8 0
3 years ago
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