On a given downstroke, what's the average angular velocity of the wing?
1 answer:
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To solve this problem we must simply resort to Newton's second law as well as the relationship between pressure and force as a physical unit applied in a given area.
In mathematical terms the Weight can be expressed as
Where,
m = mass
g = Gravitational Acceleration
We have the mass and the gravitational acceleration therefore the Weight is
Replacing we have
In this way the pressure exerted according to the active Area is,
Therefore the pressure difference between the lower and upper surface of the wings is 9.14kPa
Answer:
The magnitude of the induced Emf is
Explanation:
The width of the truck is given as 79inch but we need to convert to meter for consistency, then
The width= 79inch × 0.0254=2.0066 metres.
Now we can calculate the induced Emf using expresion below;
Then the
Where B= magnetic field component
L= width
V= velocity
=(40*10^-6) × (42) × (2.0066)
=0.003371V
Therefore, the magnitude emf that is induced between the driver and passenger sides of the truck is 0.003371V