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4 years ago

5

A runner with a mass of 62 kg running at speed of 0.8m/s

1 answer:

sashaice [31]4 years ago

6 0

Answer:

so the kinetic energy is 20Nm

Explanation:

mass of the body=m=62kg

velocity of the body=v=0.8m/s

K.E.=?

AS WE KNOW THAT

K.E.= $\frac{1}{2}$ mv²

putting values

K.E.= $\frac{1}{2}}$ ×62kg×(0.8m/s)²

K.E.=31kg×0.64m²/s²

K.E.=19.84Nm≈20Nm

i hope it will help you:)

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An isotropic point source emits light at wavelength 510 nm, at the rate of 170 W. A light detector is positioned 410 m from the

Wewaii [24]

Answer:

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Explanation:

As we know that the power emitted by the source is given as

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now we know that

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now we know that energy density is given as

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now we have

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intensity is defined as

$I = \frac{P}{A}$

now we have

$\frac{I}{c} = u = \frac{B^2}{2\mu_0}$ [/tex]

now we have

$\frac{dB}{dt} = \omega B$

$\frac{dB}{dt} = \frac{2\pi c B}{\lambda}$

$\frac{dB}{dt} = \frac{2\pi c \sqrt{2\mu_0 I}}{\lambda\sqrt c}$

here we have

$I = \frac{P}{4\pi r^2}$

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$I = 8.05 \times 10^{-5}$

now we have

$\frac{dB}{dt} = \frac{2\pi\sqrt{2\mu_0 c (8.05 \times 10^{-5})}}{(510 nm)}$

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3 years ago

If v lies in the first quadrant and makes an angle Ï/3 with the positive x-axis and |v| = 4, find v in component form.

Alexeev081 [22]

Answer:

$v=$

Explanation:

We are given that

Magnitude of vector v= $\mid v\mid =4$

v lies in the first quadrant

$\theta=\frac{\pi}{3}$

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$v_y=\mid v\mid sin\theta$

Substitute the values then we get

$v_x=4cos\frac{\pi}{3}$

$v_x=4\times \frac{1}{2}=2$

$cos\frac{\pi}{3}=\frac{1}{2}$

$v_y=4\times sin\frac{\pi}{3}=4\times \frac{\sqrt 3}{2}=2\sqrt 3$

$sin\frac{\pi}{3}=\frac{\sqrt 3}{2}$

Therefore, the vector v in component form $=$

$v=$

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