Question

A charge of 4.5 × 10-5 C is placed in an electric field with a strength of 2.0 × 104 . What is the electric force acting on the charge?

Answer 1

Answer:

0.9N/C

Explanation:

-The force of a charged particle in an electric field is given by the equation;

$F=qE\\\\q-charge$

#we substitute the values of the charge and field strength:

$F=qE\\\\=4.5\times10^{-5}\times2.0\times10^4\\\\=0.9 \ N/C$

Hence, the electric force acting on the charge is 0.9N/C