If at a particular instant and at a certain point in space the electric field is in the x-direction and has a magnitude of 3.70
1 answer:
Answer:
the magnitude of the magnetic field is 1.23 x 10⁸ T.
Explanation:
Given;
magnitude of the electric field, E = 3.7 V/m
The magnitude of the magnetic field is calculated as;
E = cB
where;
B is the magnitude of the magnetic field
c is the speed of light = 3 x 10⁸ m/s
From the above equation, the magnetic field, B, is calculated as;
Therefore, the magnitude of the magnetic field is 1.23 x 10⁸ T.
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Answer:
Weight=686.7N, , S.G.=0.933, F=17.5N
Explanation:
So, the first value the problem is asking us for is the weight of methanol. (This is supposing there is a mass of methanol of 70kg inside the tank). We can find this by using the formula:
W=mg
so we can substitute the data the problem provided us with to get:
which yields:
W=686.7N
Next, we need to find the density of methanol, which can be found by using the following formula:
we know the volume of methanol is 75L, so we can convert that to like this:
so we can now use the density formula to find our the methanol's density, so we get:
Next, we can us these values to find the specific gravity of methanol by using the formula:
when substituting the known values we get:
so:
S.G.=0.933
We can now find the force it takes to accelerate this tank linearly at
F=ma
F=17.5N
Answer:
x = 4.4719 m
Explanation:
For answer this we will use the law of the conservation of energy, where:
First, we will call:
: the car in rest
: when the spring is compressed
so:
where M is the mass of the car, g the gravity, h the altitude, K is the constant of the spring and X is the spring compressed in stopping the ore car. So, replacing values, we get:
solving for x:
x = 4.4719 m