Answer:
The inequality that can be used to determine how many rides r and games g Tyler can pay for at the carnival is:
0.75r+0.50g≤20, where:
r is the number of rides
g is the number of games
Step-by-step explanation:
With the information provided, you can say that the amount spent at the carnival is equal to the cost per ride for the number of rides plus the cost per game for the number of games. Also, given that the statement indicates that Tyler has at most $20, the inequality would indicate that the amount spent has to be less than or equal to 20. According to this, the inequality that can be used to determine how many rides r and games g Tyler can pay for at the carnival is:
0.75r+0.50g≤20, where:
r is the number of rides
g is the number of games
Class A: 6v + 8b = 202
Class B: 12v + 16b = 284
Solve using the elimination method:
since 6v and 12v are perfect for elimination, multiply the class A equation by 2 so that the van variable cancels out:
12v + 16b = 404
12v + 10b = 284
Then subtract the bottom equation from the top:
6b = 120
b = 20
Now you know that each bus can hold 20 students.
Just plug this into one of the original equations to solve for vans:
6v + 8(20) = 202
6v + 160 = 202
6v = 42
v=7
So then you know that each van can hold 7 students.
Check:
12 (7) + 10 (20) = 284
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Answer:
C) 24
Step-by-step explanation:
8; 16 24 32 40 48
12; 24 36 48 69 72
They both have the common multiple of 24 and 48 in the intermediate multiplication since 24 is half of 48 and is the smallest multiple that is the answer.
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