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vivado [14]
4 years ago
9

Determine the length of the longest metal rod which could be stored in a rectangle box 20 cm by 50 cm by 30 cm.

Mathematics
2 answers:
navik [9.2K]4 years ago
5 0

Answer:

61.64 cm

Step-by-step explanation:

The longest metal rod which could be stored in a rectangular box will be equal to its diagonal:

\therefore \: length \: of \:metal \: rod  \\  =  \sqrt{ {l}^{2} +  {b}^{2}   +  {h}^{2} }  \\  =  \sqrt{ {20}^{2} +  {50}^{2}  +  {30}^{2}  }  \\  =  \sqrt{400 + 2500 + 900}  \\  =  \sqrt{3800}  \\  = 61.64414 \\  = 61.64 \: cm

gavmur [86]4 years ago
5 0

Answer:

62 cm

Step-by-step explanation:

D = √(20² + 50² + 30²)

= √(400 + 2500 + 900)

= √3800

= √38*10²

= 10√38

≈ 61.64

≈ 62 cm

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Answer:

Step-by-step explanation:

There are four values 46, 51, 53, 59

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sampler     median     samler     median

46.46              46          53.46         49.5

46.51               48.5        53.51          52

45..53              49.5        53.53         53

46.59               52.5        53.59         56

51.46                 48.5        59.46        52.5

51.51                   51           59.51           55

51.53                   52          59.53          56

51.59                   55          59.59          59

sampling distribution of the median

median                   probability

46                               1/16

48.5                             2/16      

49.5                             2/16  

52.5                             2/16    

51                                  1/16

52                                2/16

55                                 2/16

53                                  1/16

56                                  2/16

59                                   1/16    

6 0
3 years ago
If the perimeter of a rectangle is 318 inches, find the width and length. what's the answer?
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Is there any other known values?
7 0
4 years ago
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A rectangle is 3 feet longer than it is wide. Write the equation for the perimeter of the rectangle.
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Let x be the width of the rectangle
Therefore length=3+x
Thus the formula to find the perimeter of the rectangle is:2(3+x+x)

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4 0
3 years ago
A pole 5 feet tall is used to support a guy wire for a tower, which runs from the tower to a metal stake in the ground. After pl
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The length of the guy's wire to the nearest foot is 89 feet.

The situation forms a right-angled triangle.

<h3>Properties of a right angle triangle:</h3>
  • A right-angle triangle has one angle of 90 degrees.
  • The sides can be found using the Pythagoras theorem.
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The hypotenuse of the triangle is the length of the wire.

let's use the smaller triangle to find the angle opposite the tower. Therefore,

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∅ = tan⁻¹ 2.5

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Therefore,

cos 68.20 = adjacent / hypotenuse

cos 68.20 = 33 / hypotenuse

hypotenuse = 33 / cos 68.20

hypotenuse = 88.8606843161

Therefore,

length of wire ≈ 89 feet.

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3x - 8 = 2x + 15
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