3 years ago

Rewrite the expression using only positive integer exponents.

Mathematics

1 answer:

boyakko [2]3 years ago

7 0

What expression? You need to add a picture.

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F(x) = x2 + 1 g(x) = 5-x (f+g)(x) = O x2 + x-4 x²+x+4 O x2-x+6 O x2 + x + 6

charle [14.2K]

Answer:

$\boxed{(f + g)(x) = {x}^{2} - x + 6}$

Given:

$f(x) = {x}^{2} + 1 \\ \\ g(x) = 5 - x$

To Find:

$(f + g)(x) = f(x) + g(x)$

Step-by-step explanation:

$= > f(x) + g(x) = ({x}^{2} + 1) + (5 - x) \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = {x}^{2} + 1 + 5 - x\\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = {x}^{2} + 6 - x\\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = {x}^{2} - x + 6$