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kap26 [50]
3 years ago
5

When the length of each side of a square is increased by 5 cm, its area is increased by 895 cm2. Find the length of a side befor

e the increase.
The length of a side before the increase is...
Mathematics
1 answer:
Ann [662]3 years ago
7 0

Answer:

Step-by-step explanation:

Increasing the side length by 5 is represented as s + 5. To get the area of a square we multiply side times side: (s+5)^2=s^2+10s+25

The area of a square is s². If we are increasing this area s² by 895, then to represent this we have s² + 895.

Put that together into an equation:

s^2+10s+25=s^2+895 and simplify to

10s = 870 so

s = 87

Let's check that. The area before the addition to the side is 87*87 = 7569; the area after the addition of 5 cm is 92*92 = 8464. The difference is

8464 - 7569 = 895 so we did good!

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ohaa [14]

The function is

  • y=2x^3+2x^2-19x+20

Graph attached

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4 0
2 years ago
Share R86,70 in the ratio 2 : 1​
rusak2 [61]

Answer:

2:1

2=5780

1=2890

Step-by-step explanation:

2/2+1=2/3×86,70=5780

1/2+1=1/3×8670=2890

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3 years ago
Below are 36 sorted ages of an acting award winner. Find P80.
blsea [12.9K]
P80 = 36 * 0.80 = 28.8

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3 0
3 years ago
Read 2 more answers
Put the linear inequality into slope-intercept form.
Ugo [173]

Answer:

y ≤\frac{7}{4}x - 5

Step-by-step explanation:

We are to put the linear inequality;

7x - 4y ≥ 20

in slope intercept form.

We can rearrange the inequality as;

-4y ≥ - 7x + 20

Dividing throughout by -4 we get;

y ≤ \frac{7}{4} x - 5

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8 0
3 years ago
(50 points) Could someone help me with this? Part A: Solve –mk – 90 &gt; 85 for m. Part B: Solve 3c – 5f = 55 for f. Show your w
PilotLPTM [1.2K]

A:

-mk - 90 > 85

-mk - 90 + 90 > 85 + 90

-mk > 175

-mk / k > 175 / k

-m > 175/k

-m * -1 < 175/k * -1

m < -175/k


Part B:

3c - 5f = 55

3c - 5f - 3c = 55 - 3c

-5f = 55 - 3c

-5f/5 = (55 - 3c) / 5

-f = 55/5 - 3c/5



6 0
3 years ago
Read 2 more answers
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