Answer:
Option B. y = 2x; 20 feet
Step-by-step explanation:
1. Determination of the equation that represents the relationship.
Let y be the distance travelled.
Let x be the time taken.
Let K be the speed.
From the question given above, the following data were obtained:
Distance (y) = 80 ft
Time (x) = 40 s
Speed (k) =.?
Speed = Distance /time
K = y/x ......... (1)
K = 80/40
K = 2 ft/s
Substitute the value of k into equation 1
K = y/x
K = 2 ft/s
2 = y/x
Cross multiply
y = 2x
Therefore, the equation that represents the relationship is y = 2x
2. Determination of the distance travelled in 10 s.
Speed (k) = 2 ft/s
Time (x) = 10 s
Distance (y) =.?
y = 2x
y = 2 × 10
y = 20 ft
Therefore, the person will travel 20 feet in 10 seconds.
From the above calculations, the right answer to the question is
Option B. y = 2x; 20 feet
<span>: 2s + 3t = 28, 2s = 28 - 3t s = 14 - 3t/2 Substitute s into second equation 5s + 6t = 61, 5(14 - 3t/2) + 6t = 61, 70 - 15t/2 + 6t = 61, 70 - 3t/2 = 61, 3t/2 = 9, t = 6. We can then substitute t back into first equation: 2s + 3t = 28, 2s + 3 * 6 = 28, 2s = 10, s = 5. So the final answer is: s = 5 t = 6</span>
I believe that its true hby?.
I Think First You Would Need To Turn It Into A Improper Fraction Then Divide The Denominator Into The Numerator .. Simply If Needed
