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egoroff_w [7]
4 years ago
15

Factorise: 4ay-2y can’t seem to do this

Mathematics
1 answer:
qaws [65]4 years ago
4 0
In order to factor, we must pull out factors common to each term. In this case, each term has factors of 2 and y:

4ay = 2 * 2 * a * y
2y   = 2 * y

So, we'll pull out the 2y:

2y(2a-1)

To check, distribute the 2y back through the terms in parentheses to ensure you end up with the original expression 4ay - 2y.
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dangina [55]

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8 0
2 years ago
I need help on pages 18 3-7 I’ll give you brainliest
Basile [38]
Take a pic of it or look it up on safari or download slander it has ALOT of math book answers like this one
6 0
4 years ago
What is 3 times 3/11 ??????​
Zanzabum

Answer:

0.8181818

Step-by-step explanation:

3/11×3 = 0.8181

7 0
3 years ago
Read 2 more answers
1+4=5 2+5=12 3+6=21 8+11=?
g100num [7]
I think the pattern is that you multiply the first number by the second , then add the first number. SO:
e.g. for the first one 1 x 4 = 4 , 4 + 1 = 5
for the second one 2 x 5 = 10, 10 + 2 = 12...
So for 8+11:
you do 8 x 11 = 88 , 88 + 8 = 96
7 0
3 years ago
Could someone please help me out? I've tried to solve this but I'm really having some trouble with it. Please try to explain it
guajiro [1.7K]

To find the area of the shaded region you need find the area of the shaded region and subtract the area of the unshaded region.

Area of a rectangle = width x length

A = (x + 10) x (2x + 5)

Next apply FOIL or First Outer Inner Last

A = (x * 2x) (x * 5) (10 * 2x) (10 * 5)

A= 2x2 + 5x + 20x + 50

A= 2x2 +25x +50

 

Area of a square=  sides2

A= (x + 1)2

A= (x+1) (x+1)

Next apply FOIL or First Outer Inner Last

A = (x *x) (1*x) (1*x) (1*1)

A = x2 + 1x + 1x +1

A= x2 + 2x +1

 

A= 2x2 +25x +50 - 2x2 +25x +50

A= 50x + 100





4 0
3 years ago
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