2 years ago

Solve x^2 − 10 = 0. If necessary, round to the nearest hundredth. PLEASE HELP!!

Mathematics

1 answer:

Alex Ar [27]2 years ago

5 0

Your answer is D. ~ 3.16

You might be interested in

Please help!!!<br> Which expression is equivalent to (3m^-1n^2)^4/(2m^-2n)^3

Elza [17]

$\text{Use:}\\\\(a\cdot b)^n=a^nb^n\\\\(a^n)^m=a^{n\cdot m}\\\\\dfrac{a^n}{a^m}=a^{n-m}$

$\dfrac{(3m^{-1}n^2)^4}{(2m^{-2}n)^3}=\dfrac{3^4(m^{-1})^4(n^2)^4}{2^3(m^{-2})^3n^3}=\dfrac{81m^{-4}n^8}{8m^{-6}n^3}\\\\=10.125m^{-4-(-6)}n^{8-3}=10.125m^2n^5$

7 0

2 years ago

Read 2 more answers

I NEED HELP LOL<br><br> What is the value of g(-4)?

Elena L [17]

Answer:

C. 1

Step-by-step explanation:

Use the first one since it is -4 so

6 0

2 years ago

Please list a reason why scientific notation is important thank youuu !!

otez555 [7]

The primary reason why scientific notation is important is that it allows us to convert very large or very small numbers into much more manageable sizes. When these numbers are in scientific notation, it is much easier to work with them

6 0

2 years ago

Prove the theorem (AB )^T= B^T. A^T

Lisa [10]

Answer:

$(AB)^T = B^T.A^T (Proved)$

Step-by-step explanation:

Given (AB )^T= B^T. A^T;

To prove this expression, we need to apply multiplication law, power law and division law of indices respectively, as shown below.

$(AB)^T = B^T.A^T\\\\Start, from \ Right \ hand \ side\\\\B^T.A^T = \frac{B^T.A^T}{A^T}.\frac{B^T.A^T}{B^T} (multiply \ through) \\\\ = \frac{A^{2T}.B^{2T}}{A^T.B^T} \\\\=\frac{(AB)^{2T}}{(AB)^T} \ \ (factor \ out \ the power)\\\\= (AB)^{2T-T} \ (apply \ division \ law \ of \ indices; \ \frac{x^a}{x^b} = x^{a-b})\\\\= (AB)^T \ (Proved)$

3 0

3 years ago

(Repost) please help what is 7 7/10 rounded to the nereast whole number?? please explain your answer if you got it cause I can L

Finger [1]

It’s eight because 7 can round up so it changed to eight

7 0

2 years ago

Read 2 more answers