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3 years ago

You deposit 1600 in a bank Find the balance after 3 years if the account pays 4%annual interest yearly.

Mathematics

1 answer:

saveliy_v [14]3 years ago

5 0

Answer:

192

Step-by-step explanation:

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BRAINLIEST AND POINTS!!!<br><br> PLEASE EXPLAIN

timofeeve [1]

Answer:

Option C. $\$23,134.61$

Step-by-step explanation:

we know that

$A=\frac{P[(1+r)^{n} -1]}{r(1+r)^{n}}$

we have

$P=\$400$

$r=0.075/12=0.00625$

$n=6*12=72\ months$

substitute in the formula

$A=\frac{400[(1+0.00625)^{72} -1]}{0.00625(1+0.00625)^{72}}\\ \\A=\frac{226.446972}{0.009788}\\ \\A=\$23,134.61$

4 0

2 years ago

Which of the given functions could this graph represent? A. f(x) = x(x − 1)(x − 2)(x + 1)(x + 2) B. f(x) = x(x − 1)(x + 1) C. f(

zaharov [31]

Answer:

The answer is B. f(x) = (x − 1)(x − 2)(x + 1)(x + 2)

Step-by-step explanation:

5 0

2 years ago

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Anika was shown a reduction of a complex figure.

Luba_88 [7]

Answer:

The scale factor will be 0.25 and the length of the side will be 8.75 cm. Hope it helps :)

Step-by-step explanation:

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2 years ago

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Wait are these right?! PLS

Korolek [52]

Answer:

yes they are good job

Step-by-step explanation:

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2 years ago

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Calculus= Integrate 5^x dx please break down how answer is 1/6x^6+C

aleksley [76]

Answer:

$\int\limits {5^x} \, dx = \frac{5^x}{ln\ x} + c$

Step-by-step explanation:

Note that the integral of $5^x$ is not $\frac{1}{6}x^6 + c$

The solution is as follows:

Given

$5^x$

Required

Integrate

Represent the given expression using integral notation

$\int\limits {5^x} \, dx$

This question can't be solved directly;

We'll make use of exponential rules which states;

$\int\limits {a^x} \, dx = \frac{a^x}{ln\ x} + c$

By comparing $\int\limits {5^x} \, dx$ with $\int\limits {a^x} \, dx$ ;

we can substitute 5 for a;

Hence, the expression $\int\limits {a^x} \, dx = \frac{a^x}{ln\ x} + c$ becomes

$\int\limits {5^x} \, dx = \frac{5^x}{ln\ x} + c$

-------------------------------------------------------------------------------------

However, the integral of $x^5$ is $\frac{1}{6}x^6 + c$

This is shown below:

Given that $x^5$

Applying power rule;

Power rule states that

$\int\limits{x^n}\ dx = \frac{x^{n+1}}{n+1} + c$

In this case ( $x^5$ ), n = 5;

So, $\int\limits{x^n}\ dx= \frac{x^{n+1}}{n+1} + c$

becomes

$\int\limits{x^5}\ dx = \frac{x^{5+1}}{5+1} + c$

$\int\limits{x^5}\ dx = \frac{x^{6}}{6} + c$

$\int\limits{x^5}\ dx= \frac{x^{6}}{6} + c$

4 0

3 years ago