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katovenus [111]

3 years ago

11

Solve equation

3} = 3" alt="\frac{k-4}{3} = 3" align="absmiddle" class="latex-formula">

1 answer:

3241004551 [841]3 years ago

6 0

k-4/3= 3

Mutiply both sides by 3 .

(3)(k-4/3)= (3)(3)

Cross out 3 and 3 , divide by 3 and then becomes k-4= 9

Move -4 to the other side

Sign changes from -4 to +4

k-4+4= 9+4

k= 13

Answer: k= 13

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Find the first partial derivatives of the function f(x,y,z)=4xsin(y−z)

Amanda [17]

Answer:

$f_x(x,y,z)=4\sin (y-z)$

$f_x(x,y,z)=4x\cos (y-z)$

$f_z(x,y,z)=-4x\cos (y-z)$

Step-by-step explanation:

The given function is

$f(x,y,z)=4x\sin (y-z)$

We need to find first partial derivatives of the function.

Differentiate partially w.r.t. x and y, z are constants.

$f_x(x,y,z)=4(1)\sin (y-z)$

$f_x(x,y,z)=4\sin (y-z)$

Differentiate partially w.r.t. y and x, z are constants.

$f_y(x,y,z)=4x\cos (y-z)\dfrac{\partial}{\partial y}(y-z)$

$f_y(x,y,z)=4x\cos (y-z)$

Differentiate partially w.r.t. z and x, y are constants.

$f_z(x,y,z)=4x\cos (y-z)\dfrac{\partial}{\partial z}(y-z)$

$f_z(x,y,z)=4x\cos (y-z)(-1)$

$f_z(x,y,z)=-4x\cos (y-z)$

Therefore, the first partial derivatives of the function are $f_x(x,y,z)=4\sin (y-z), f_x(x,y,z)=4x\cos (y-z)\text{ and }f_z(x,y,z)=-4x\cos (y-z)$ .

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4 years ago

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Answer:

15ft

Step-by-step explanation:

a^2 + b^2 = c^2

12 or 9 can equal to b or a

12^2 + 9^2 = c^2

144 + 81 = c ^2

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3 years ago

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Step-by-step explanation:

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-7x^2 - x - 10

This result is in "standard form."

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3 years ago

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Step-by-step explanation:

<u>Concept</u><u> </u><u>Used </u><u>:</u><u>-</u>

The measure of a straight line is 180°. So the sum of angles on a straight line is 180° .

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