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Verdich [7]
3 years ago
6

What would happen to the boiling point of water at 8,000 m above sea level, where air pressure is lower?

Chemistry
1 answer:
mario62 [17]3 years ago
5 0
it will get warm or spread out into the water or
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Elements with similar properties are located
Nataly [62]
Those elements with similar properties are in the same column.
4 0
3 years ago
Find the number of moles of water that can be formed if you have 170 mol of hydrogen gas and 80 mol of oxygen gas. Express your
Sav [38]

<u>Answer:</u> The amount of water that can be formed is 160 moles

<u>Explanation:</u>

We are given:

Moles of hydrogen gas = 170 moles

Moles of oxygen gas = 80 moles

The chemical equation for the reaction of hydrogen gas and oxygen gas follows:

2H_2+O_2\rightarrow 2H_2O

By Stoichiometry of the reaction:

1 mole of oxygen gas reacts with 2 moles of hydrogen gas

So, 80 moles of oxygen gas will react with = \frac{2}{1}\times 80=160mol of hydrogen gas

As, given amount of hydrogen gas is more than the required amount. So, it is considered as an excess reagent.

Thus, oxygen gas is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

1 mole of oxygen gas produces 2 moles of water

So, 80 moles of oxygen gas will produce = \frac{2}{1}\times 80=160moles of water

Hence, the amount of water that can be formed is 160 moles

3 0
3 years ago
If 7.0 mol sample of a gas has a volume of 12.2 L, what would the volume be if the amount of gas was increased to 16.8 mol
Leviafan [203]

Answer:

V_{2} = 29.28\,L

Explanation:

Let assume that gas behaves ideally and experiments an isobaric and isothermal processes. The following relationship is applied to determined the final volume:

\frac{V_{1}}{n_{1}} = \frac{V_{2}}{n_{2}}

V_{2} = V_{1} \cdot \left(\frac{n_{2}}{n_{1}} \right)

V_{2} = (12.2\,L)\cdot \left(\frac{16.8\,moles}{7\,moles} \right)

V_{2} = 29.28\,L

5 0
3 years ago
Which statement best explains the net transfer of energy that is about to
ArbitrLikvidat [17]

Answer:

Explanation:

B I got it right

8 0
2 years ago
Read 2 more answers
2 Calculate What is the density of a liquid with a mass of 17.4g<br> and a volume of 20 mL?
jolli1 [7]

Answer:

P= 0.87g/mL or 0.87g/cm^3

Explanation:

P=m/v

P=density

P=17.4g/20mL

P= 0.87g/mL

1mL=1cm^3

8 0
3 years ago
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