How many calories of are required to heat 731 grams of water from 35°c to 83°c? (assume that the specific heat of water is 1.00
2 answers:
Answer:
The calories required = 35088
Explanation:
The heat required can be calculated by using specific heat of the water and mass and temperature raised.
The specific heat of water is the amount of heat required to raise the temperature of one gram of water by one degree celsius
Thus
Heat required = mass of water X specific heat X change in temperature
Given:
Specific heat of water = 1 cal /g °C
mass of water = 731 g
change in temperature = 83-35 = 48°C
Putting values
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Answer:
2 moles
Explanation:
Let us first start by calculating the molecular mass of Al₂O₃.
The mass of a mole of any compound is called it's molar mass. 1 molar mass 6.02 X 10²³, or Avogadro's number, of compound entities.
Say, 1 mole of Al₂O₃ has 6.02 X 10²³ of Al₂O₃ molecules/atoms. It also has 2*6.02 X 10²³ number of Al atoms and 3*6.02 X 10²³ number of O atoms.
Molecular mass of Al : 26.981539 u
Molecular mass of O: 15.999 u
Therefore, molecular mass of Al₂O₃ is:
= u
= 101.960078 u
This can be approximated to 102 u.
1mole weighs 102 u
So, 2moles will weigh 2*102 = 204 u