Question

What is the final concentration of the solution produced when 225.5 mL of 0.09988-M solution of Na2CO3 is allowed to evaporate until the solution volume is reduced to 45.00 mL?

Answer 1

Explanation:

The given data is as follows.

       $V_{1}$ = 225.5 mL,             $V_{2}$ = 45.00 mL

       $M_{1}$ = 0.09988 M,          $M_{2}$ = ?

Therefore, formula to calculate final concentration will be as follows.

                  $M_{1}V_{1}$ = $M_{2}V_{2}$

Putting the given values into the above formula as follows.

            $M_{1}V_{1}$ = $M_{2}V_{2}$

   $0.09988 M \times 225.5 mL$ = $M_{2} \times 45.0 mL$

                    $M_{2}$ = 0.5 M

Thus, we can conclude that the final concentration of the given solution is 0.5 M.