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madam [21]
3 years ago
15

HELP PLEASE! I am so bad at this I feel so dumb

Mathematics
1 answer:
VikaD [51]3 years ago
7 0

Answer:

i hate math too 737

Step-by-step explanation:

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A chemist reacted 17.25 grams of sodium metal with an excess amount of chlorine gas. The chemical reaction that occurred is show
DanielleElmas [232]

Answer:

<em><u>A chemist reacted 17.25 grams of sodium metal with an excess amount of chlorine gas. The chemical reaction that occurred is shown.</u></em>

<em><u>A chemist reacted 17.25 grams of sodium metal with an excess amount of chlorine gas. The chemical reaction that occurred is shown.__Na + __ Cl2 → __ NaCl</u></em>

<em><u>A chemist reacted 17.25 grams of sodium metal with an excess amount of chlorine gas. The chemical reaction that occurred is shown.__Na + __ Cl2 → __ NaClIf the percentage yield of the reaction is 88%, what is the actual yield? Show your work, including the use of stoichiometric calculations and conversion factors. </u></em>

7 0
3 years ago
How do u do 6x32 and 7x29 using distribuative property to solve
Rufina [12.5K]

Answer:

use multiple the numbers to get the co rrect

Step-by-step explanation:

32×6

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29×7=203

4 0
3 years ago
Read 2 more answers
A fair dice has six sides, numbered 1 to 6
Ivanshal [37]

Answer:

a. 1/6

Step-by-step explanation:

for a, there is only one side that has three

8 0
3 years ago
What is the measure of angle Z in the parallelogram shown?
Anarel [89]

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Step-by-step explanation:

8 0
3 years ago
Which of the following sets of data will have the smallest Standard Deviation?
uranmaximum [27]

Answer: D

Step-by-step explanation:

Standard Deviation σ2 =

Σ(xi - μ)2/N

=(1 - 5.3)2 + ... + (9 - 5.3)2/10

=68.1/10

= 6.81

σ = √6.81

= 2.60959767014

B) σ2 =

Σ(xi - μ)2/N

=(3 - 61.7)2 + ... + (99 - 61.7)2/10

=58414.1/10

= 5841.41

σ = √5841.41

= 76.429117488036

C) (1 - 11.4)2 + ... + (1 - 11.4)2/10

=8758.4/10

= 875.84

σ = √875.84

= 29.59459410095

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=0/10

= 0

σ = √0

= 0

I hope this helps, mark as Brainliest please.

6 0
3 years ago
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