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Lena [83]
3 years ago
5

What type of circuit measurement is made by placing a meter’s test leads in parallel with a deenergized component?

Mathematics
1 answer:
sladkih [1.3K]3 years ago
3 0
The answer is that you are measuring "resistance".

If the segment is DE-energized, which means the entire device is shut down, at that point the main thing you can quantify with the meter- probes on the two ends of the segment is its resistance. The ordinary meter measures volts, amps, and ohms. If you touch 
the probes to the two ends of the part and the circuit is empowered, at that point you measure the voltage over the component.  If the circuit is DE-energized, at that point you are  measuring the component's resistance.
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-5x -10 >30 help Hehehehehe.
Mnenie [13.5K]

Answer:

x<-8

Step-by-step explanation:

-5x-10>30

(add 10 to both sides)

-5x-10+10>30+10

-5x>40

\frac{-5x}{-1}<\frac{40}{-1}

(dividing through by -1 changes the sign of the inequality from "<" to ">")

5x<-40

(dividing through by 5)

\frac{5x}{5}<\frac{-40}{5\\}

x<-8

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Solve 16x + 9 = 9y – 2x for y.<br> y =
liberstina [14]
Y= 2x + 1, hope this helps
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The reciprocal of the cosine is the ___.
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Answer:

The correct answer is A

Step-by-step explanation:

The secant is the distance from the center to the vertical tangent in a certain direction.

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The length of a DNA nucleotide building block is about 1 nanometer, or 0.000000001 meters. Fill in the blank to write this numbe
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Step-by-step explanation:

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Which equation represents the line that passes through (5,8) and (9,2)
Dahasolnce [82]
ASSUMING This is a straight line so we gotta the formula for a straight line which is y=mx+b, where m represents the slope and b represents the y intercept.

First, we know this line passes through (5,8) and (9,2) we can use these for finding the equations. When we know two points, we use this formula:

y-y=m(x-x)

The first y is 8 and the second one is 2
The first x is 5 and the second one is 9

Plug it in:

8-2=m(5-9)
6=m(-4)
6/-4=m <— simplify this
m= -3/2

*NOTE: another way to find m is by calculating it (y-y)/(x-x)

Now we know m, we have to find b.
All you gotta do is plug everything you know back into the equation y=mx+b

y=mx+b
y=-3/2x+b <— now plug in a point we know(x,y)

8=-3/2(5)+b
8=-15/2+b
8-(-15/2)=b
b=8+15/2
b=16/2+15/2
b=31/2 (now you can write be as a fraction or a decimal in your equation, depending on what your teacher told you to use)
*NOTE: it is best to use fractions instead of decimals as it is more accurate sometimes.

Now we know all the variables that need to be known, we just need to rewrite the formula of the equation so the teacher can see.

m=-3/2
b=31/2

We don’t need to plug in x or y since it could have different values (since a straight line has MANY co-ordinates)

SO OUR EQUATION IS=
y=(-3/2)x+31/2

Hope you understand this, feel free to ask me anything!

6 0
3 years ago
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