Answer:
Explanation:
From the given information:
Since the parent are normal; Let assume that their trait is Pp
The affected sister will be recessive in nature, so the trait will be pp
Now, the husband who is the groom will be a carrier with a probability of 2/3 since her sister is affected.
Also, the wife will be carrying a heterozygous trait since she is normal as well.
However, using Hardy-Weinberg assumption:
q = 0.02
Recall that:
Thus, 
2pq = 0.0392
Finally, the required probability that there will be an affected offspring amongst the family is:
The correct answer is option A, that is, placer deposits.
The concentration of heavy deposits known as the placer deposits are produced by the gravitational action, generally found in streams. The minerals that take place as placer deposits comprise copper, gold, magnetite, cassiterite, and copper.
The formation of placer deposits takes place when the metal-bearing rock on land is weathered and the generated debris is washed down to the sea by the rivers. Further by the action of waves, currents, and rides the particles of heavy metal gets amassed to produce mineral sand deposits. These generally occur as beach deposits.
So this my friend is a Contact Force. Anything that involves pushing, pulling, or creating friction is a contact force. So you will say it’s a contact force. Please Mark me brainliest
Answer:
16.66 %
Explanation:
The receptors that are bound with the ligand can be calculated by the formula as follows:
Kd = [R] [L]/[RL]
Here, Kd is dissociation constant = 1.5 mM
R is free receptor concentration = 10 mM
L is free ligand concentration = 2.5 mM
The values needs to be constitute to find the percentage of receptors that are bound to ligand.
Put all the values
1.5 = 10 × 2.5 / RL or RL = 25 /1.5
So RL = 16.66
Hence 16.66 % of receptor is bound to substrate.
Thus, the answer is 16.66%
