Answer:
427.392 kJ
Explanation:
m = Mass of gas = 4.5 kg
Initial temperature = 200 K
Final temperature = 360 K
R = Mass specific gas constant = 296.8 J/kgK
= Specific heat ratio = 1.5
Work done for a polytropic process is given by
The work input during the process is -427.392 kJ
Answer:
M = 49.4kgm/s (towards the left)
Explanation:
Momentum is the product of mass and velocity of an object
Momentum = mass * velocity
Momentum of Object 1 with mass 1.66 kg moving to the right at 11.2 m/s, is expressed as:
M1 = 1.66 * 11.2
M1 = 18.592kgm/s
Momentum of Object 2 with mass 6.59 kg moving to the left at 10.4 m/s is expressed as:
M2 = 6.59 * -10.4
M2 = -68.536kgm/s (negative since it is moving towards the left)
The total momentum will be the sum of momentum along the x-component as shown:
M = M1+M2
M = 18.592kgm/s--68.536kgm/s
M = -49.944kgm/s
M = 49.4kgm/s (towards the left)
solution:
write the coordinates of the points A and B
A= (0,0,14)ft
B= (5,-6,0)ft
write the position vector of a with recpect to b
R_{BA}=(0-5)i+(0-(-6))j+(14-0)k
=-5i+6k+14k
calculation of a magnitude of the vector R_{BA}
\left | R_{BA} \right |=\sqrt{(-5)^2+6^2+14^2}
=\sqrt{25+36+196}
=16.031ft
calculation of the unit vector
\frac{-5i+6k+14k}{16.031}
calculation of the force
F_{BA}=R_{BA}U_{BA}
here, F_{BA} is the magnitude of the force.
substitute 350lb for F_{BA} and (\frac{-5i+6k+14k}{16.031}) for U_{BA}.
F_{BA} = 350 x (\frac{-5i+6k+14k}{16.031})
=-109.2i+131j+305.7k lb
