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11111nata11111 [884]
3 years ago
5

According to the law of conservation of mass, in a chemical reaction, the mass of the reactant will always be different from the

mass of the product.
Physics
1 answer:
Lostsunrise [7]3 years ago
6 0
That is not true.

<span>According to the law of conservation of mass, in a chemical reaction, the mass of the reactants will always be the same as the mass of the products.</span>

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The length of a wooden rod is 25.5 cm. What is this length in:<br>(a) millimetres?<br>(b) metres?​
larisa86 [58]

Answer:

(a)255mm \\ (b)0.255m

Explanation:

(a)1cm = 10mm \\ 25.5cm = x

Cross multiply

1x = 25.5 \times 10 \\ x = 255mm

(b)100cm = 1m \\ 25.5cm = x

cross multiply

100x = 25.5 \\  \frac{100x}{100}  =  \frac{25.5}{100}  \\ x = 0.255m

hope this helps

brainliest appreciated

good luck! have a nice day!

4 0
4 years ago
Read 2 more answers
A dragster runs the quarter mile in 8.96 s. What is the car's velocity (in ft/s) at the finish line?
lara [203]
The first thing you should know to answer this question is the following conversion:
 1mi = 5280feet
 We have then that the speed is:
 v = ((1/4) * (5280)) / (8.96)
 v = 147.32 feet / s
 Answer:
 the car's velocity (in ft / s) at the finish line is 147.32 feet / s
7 0
3 years ago
A 1300 kg car traveling with a speed of 3.5 m/s executes a turn with a 8.5 m radius of curvature.
Y_Kistochka [10]

Answer:

1.4 m/s/s (2.s.f)

Explanation:

The formula for centripetal acceleration is:

a=\frac{v^{2} }{r}, where v is velocity and r is the radius.

In the question we are given the information that the car has a mass of 1300kg, a velocity of 2.5m/s, and a turn radius of 8.5m which are all the values we need. Therefore we can simply substitute in the values to solve the question:

a=\frac{3.5^{2} }{8.5} \\a=1.4

Therefore the centripetal acceleration of the car is 1.4m/s/s. (2.s.f)

Hope this helped!

7 0
3 years ago
A balloonist happens to drop his metal ballpoint pen from his balloon as he is taking notes on his flight. Because his pen has a
Lerok [7]
So this is dealing with the conservation of energy. So you set kinetic energy equal to potential energy, so it looks like this:

1/2mv^2=mgh. The m's cancel out, so it is 1/2v^2=gh.

To find out what the height h is, divide g on both sides, so...

h=0.5v^2/g. v=22m/s, g=9.81m/s^2, so h=(0.5)(22^2)/(9.81)=24.67m
5 0
3 years ago
In a football game, a 90 kg receiver leaps straight up in the air to catch the 0.42 kg ball the quarterback threw to him at a vi
irinina [24]

To solve this problem it is necessary to apply the equations related to the conservation of momentum. Mathematically this can be expressed as

m_1v_1+m_2v_2 = (m_1+m_2)v_f

Where,

m_{1,2}= Mass of each object

v_{1,2} = Initial velocity of each object

v_f= Final Velocity

Since the receiver's body is static for the initial velocity we have that the equation would become

m_2v_2 = (m_1+m_2)v_f

(0.42)(21) = (90+0.42)v_f

v_f = 0.0975m/s

Therefore the velocity right after catching the ball is 0.0975m/s

8 0
3 years ago
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