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11111nata11111 [884]
3 years ago
5

According to the law of conservation of mass, in a chemical reaction, the mass of the reactant will always be different from the

mass of the product.
Physics
1 answer:
Lostsunrise [7]3 years ago
6 0
That is not true.

<span>According to the law of conservation of mass, in a chemical reaction, the mass of the reactants will always be the same as the mass of the products.</span>

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The gravitational force between two objects is 2400 N. What will be the gravitational force between the objects if the mass of o
motikmotik

Answer:

4800N

Explanation:

Lets assume,

Mass of first object = m₁

Mass of second object = m₂

Distance between the two objects = r

Thus the force between the two objects will be

F = \frac{G\times m_{1}\times m_{2}}{r^{2}}

where, G = Universal gravitational constant

Given, F = 2400N

New mass of second object = 2m₂

Now, the force will be

F_{2} = \frac{G\times m_{1}\times 2m_{2}}{r^{2}}

F_{2}= 2\frac{G\times m_{1}\times m_{2}}{r^{2}}

F_{2}= 2F

F_{2}= 2\times2400

Thus, F₂ = 4800N

6 0
3 years ago
Who reported four “element” classifications, but included some substances that were combinations of elements rather than true el
notsponge [240]
Antoine-Laurent Lavoisier was the first person to report the four element classification system but also ended up including some compounds rather than elements.
7 0
3 years ago
After a laser bean passes through two thin parallel slits, thefirst completely dark fringes occur at ± 15.00with the original di
PSYCHO15rus [73]

Answer:

143 °

Explanation:

a ) If d be the distance between slits , λ be wavelength of light used and at angle θ nth dark fringe is formed then

d sinθ = ( 2n+1) λ/2

for first dark fringe

d sinθ = λ/2

d /λ = 1/ 2 sinθ

1 / 2 sin15

= 1.93

b )

For intensity of fringe at angle θ,  the relation is

I = I₀ cos²θ

I / I₀  = cos²θ/2

Given I / I₀ =0. 1

0.1 = cos²θ/2

θ/2 = 71.5

θ = 143 °

4 0
3 years ago
A small balloon is released at a point 150 feet away from an observer, who is on level ground. If the balloon goes straight up a
Elza [17]

Answer:

\dfrac{dz}{dt}=0.65\ ft/s

Explanation:

Given that

x= 150 ft

\dfrac{dy}{dt}= 7\ ft/s

y= 14 ft

From the diagram

z^2=x^2+y^2

When ,x= 150 ft and y= 14 ft

z^2=150^2+14^2

z=\sqrt{150^2+15^2}

z=150.74 ft

z^2=x^2+y^2

By differentiating with respect to time t

2z\dfrac{dz}{dt}= 2x\dfrac{dx}{dt}+2y\dfrac{dy}{dt}

z\dfrac{dz}{dt}= x\dfrac{dx}{dt}+y\dfrac{dy}{dt}

Here x is constant that is why

\dfrac{dx}{dt}=0

z\dfrac{dz}{dt}= y\dfrac{dy}{dt}

Now by putting the values in the above equation we get

150.74\times \dfrac{dz}{dt}=14\times 7

\dfrac{dz}{dt}=\dfrac{14\times 7}{150.74}\ ft/s

\dfrac{dz}{dt}=0.65\ ft/s

Therefore the distance between balloon and observer increasing with 0.65 ft/s.

5 0
3 years ago
The equation shows neutralization of an acid and a base to produce a salt and water.
Lyrx [107]
This equation will be balanced if the x is a 2 because there are two sodiums on the reactants sides so there must be two sodiums on the products side

Hope this helps
7 0
3 years ago
Read 2 more answers
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