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Answer:
Step-by-step explanation:
3x+y=-4 (1)
3x-4y=6 (2)
<em><u>solving by elimination:</u></em>
(1) - (2) ⇒
3x + y = -4
3x - 4y = 6
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0 + 5y = -10
5y = -10 ⇔ y = -2
(2) ⇒ 3x-4y=6 ⇒ 3x-4(-2)=6 ⇒ 3x = 6 - 8 = -2 ⇒ x = -2/3
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:)
Answer:
Step-by-step explanation:
Absolute Value Inequality entered :
|y+2|>6
Step by step solution :
Step 1: Rearrange this Absolute Value Inequality
Absolute value inequalitiy entered
|y+2| > 6
Step 2: Clear the Absolute Value Bars
Clear the absolute-value bars by splitting the equation into its two cases, one for the Positive case and the other for the Negative case.
The Absolute Value term is |y+2|
For the Negative case we'll use -(y+2)
For the Positive case we'll use (y+2)
Step 3: Solve the Negative Case
-(y+2) > 6
Multiply
-y-2 > 6
Rearrange and Add up
-y > 8
Multiply both sides by (-1)
Remember to flip the inequality sign
y < -8
Which is the solution for the Negative Case
Step 4: Solve the Positive Case
(y+2) > 6
Rearrange and Add up
y > 4
Which is the solution for the Positive Case
Step 5:
Wrap up the solution
y < -8
y > 4
Solutions in Interval Notation
(-∞,-8)
(4,+∞)
Solutions on the Number Line
Two solutions were found :
y > 4
y < -8
Answer:
Positive one
Step-by-step explanation:
The angle 0 does not lie in any of the four quadrants, it lands directly in between quadrants I and IV. The value of cos 0 is always 1.
Answer:
not sure
Step-by-step explanation: